Multiply both 1/6=11/66, 3/11=9/66. 1/6 is bigger.
Answer:
sory
Step-by-step explanation:
Temporarily subdivide the given area into two parts: a large rectangle and a parallelogram. Find the areas of these two shapes separately and then combine them for the total area of the figure.
By counting squares on the graph, we see that the longest side of the rectangle is the hypotenuse of a triangle whose legs are 8 and 2. Applying the Pyth. Thm., we find that this length is √(8^2+2^2), or √68. Similarly, we find the the width of this rectangle is √(17). Thus, the area of the rectangle is √(17*68), or 34 square units.
This leaves the area of the parallelogram to be found. The length of one of the longer sides of the parallelogram is 6 and the width of the parallelogram is 1. Thus, the area of the parallelogram is A = 6(1) = 6 square units.
The total area of the given figure is then 34+6, or 40, square units.
Answer:
1.) No ;
2.) - 0.931
3.) 0.1785
Step-by-step explanation:
Given :
μ = 84.3 ; xbar = 81.9 ; s = 17.3
H0 : μ = 84.3
H1 : μ < 84.3
The test statistic :
(xbar - μ) ÷ (s/√(n))
(81.9 - 84.3) / (17.3/√45)
-2.4 / 2.5789317
= - 0.9306
= - 0.931
Using the test statistic, we could obtain the Pvalue : df = n - 1 ; df = 45 - 1 = 44
Using the Pvalue calculator :
Pvalue(-0.9306, 44) = 0.1785
Using α = 0.05
The Pvalue > α
Then we fail to reject H0; and conclude that there is no significant evidence to support the claim that the mean waiting time is less than 84.3
Answer:
The interval of increase of g(x) is 
.
Step-by-step explanation:
The interval of increase occurs when first derivative of given function brings positive values. Let be 
, the first derivative of the function is:
The following condition must be met to define the interval of increase:
The first term is always position due to the quadratic form, the second one is a first order polynomial and it is known that positive value is a product of two positive or negative values. Then, the second form must satisfy this:
The solution to this inequation is:
Now, the solution to this expression in interval notation is:
