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Vsevolod [243]
2 years ago
6

the total cost of 8 pens and 9 books is $30.05. if the cost of a pen is $a, and a book is .90 MORE expensive. find A. Give your

answer in two decimal places.
Mathematics
2 answers:
AysviL [449]2 years ago
5 0

Answer:

2 Answers By Expert Tutors ... Let's set x = cost of books and y = cost of pens. ... In algebra, this can be written as x + y = 18. ... Using x and y, we get 1 book and 2 pens costs $21, or x + 2y = 21 ... The pen must cost $3 because we are adding $3 to the total when we ... Please provide a valid phone number.

Step-by-step explanation:

Kazeer [188]2 years ago
4 0
A= 2.74375 or just 3
Books= $8.10
Pens= 3 or 2.7475
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Williiam lost 25% of his marble,gave 1/6 of the remainder to his.Brother and had 120 marbles left.How many marbles did he have a
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Answer:

Number of marbles with Williams at the starting = 192

Step-by-step explanation:

Let total number of marbles with Williams = m

He lost marbles = 25% of the total number

                           = \frac{25}{100}\times m

                           = \frac{m}{4}

Remaining marbles with Williams = m - \frac{m}{4}

                                                        = \frac{3m}{4}

He gave marbles to his brother = \frac{1}{6}th of the remaining marbles

                                                    = \frac{1}{6}\times \frac{3m}{4}

                                                    = \frac{m}{8}

Remaining marbles after giving marbles to his brother = 120

Therefore, \frac{3m}{4}-\frac{m}{8}=120

\frac{6m}{8}-\frac{m}{8}=120

\frac{5m}{8}=120

m = \frac{120\times 8}{5}

m = 192

Number of marbles with Williams at the starting = 192

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Step-by-step explanation:

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