All categories

3 years ago

How do i find the radius of a cylinder with only surface area and height

Mathematics

1 answer:

tatiyna3 years ago

5 0

Answer:

you have to use this formula r = 1 /2

Square root (h2+2A /π﹣h /2)

Step-by-step explanation:

You might be interested in

Can someone pls graph this for me ? ( just screenshot and use the marker tool to graph)

Furkat [3]

Answer: Y = -4 is four numbers down for the origin. Y = 0 is basically the origin (the center of the graph)

8 0

2 years ago

Simplify 7n - 2n 3p 2p.

andrew11 [14]

$7n^{-2}n^3p^2p=7n^{-2+3}p^{2+1}=\boxed{7np^3}$

4 0

3 years ago

Which values are solutions to the inequality? 5r≤6r−8 Select each correct answer. r = 7 r = 8 r = 9 r = 10

Ratling [72]

Answer:

r = 8,9,10

Step-by-step explanation:

The given inequality is :

5r≤6r−8 ...(1)

We need to find the value of r.

Subtracting 5r to both sides of the inequality .

5r-5r≤6r-5r−8

0≤r−8

r ≥ 8

Hence, the values of r are 8,9,10.

8 0

3 years ago

Read 2 more answers

How do yo find slope

Yuliya22 [10]

X2 minus x1/y2 minus y1 is how u find slope

6 0

3 years ago

In the figure shown, ABC is a right triangle with side lengths a, b, and c, and CD is an altitude to side AB. The side lengths o

ycow [4]

Answer:

Step-by-step explanation:

In the figure shown, ABC is a right triangle with side lengths a, b, and c, and CD is an altitude to side AB. This altitude divides the triangle into two right triangles ADC and BDC. In these triangles,

$\angle CBD\cong \angle ACD\cong \angle CBA$
$\angle DCB\cong \angle DAC\cong \angle BAC$

So,

$\triangle ABC\sim \triangle CBD\sim \triangle ACD$

1. From the similarity $\triangle ABC\sim \triangle CBD,$ you have

$\dfrac{AB}{BC}=\dfrac{BC}{BD}\\ \\\dfrac{c}{a}=\dfrac{a}{s}$

2. From the similarity $\triangle ABC\sim \triangle ACD,$ you have

$\dfrac{AB}{AC}=\dfrac{AC}{AD}\\ \\\dfrac{c}{b}=\dfrac{b}{r}$

Hence, option A is true

5 0

3 years ago