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3 years ago

Use the number line to identify the least value, first quartile, median, third quartile, and greatest value of the data.

Mathematics

2 answers:

vredina [299]3 years ago

7 0

Answer: least value - 22

first quartile - 29

median - 35

third quartile - 47

greatest value - 62

Step-by-step explanation:

svetoff [14.1K]3 years ago

7 0

^^ he’s correct listen to him or her

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3 years ago

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MatroZZZ [7]

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2 years ago

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Find the distance between (-6, -5) and (2,0)

kotykmax [81]

Answer:

$\displaystyle d = \sqrt{89}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra II

Distance Formula: $\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step-by-step explanation:

Step 1: Define

Point (-6, -5)

Point (2, 0)

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d

Substitute [DF]: $\displaystyle d = \sqrt{(2+6)^2+(0+5)^2}$
Add: $\displaystyle d = \sqrt{(8)^2+(5)^2}$
Exponents: $\displaystyle d = \sqrt{64+25}$
Add: $\displaystyle d = \sqrt{89}$

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3 years ago