The velocity, slope, of a line is always (y2-y1)/(x2-x1), in this case:
slope=(8-2)/(7-9)=6/-2=-3
m=-3
To answer your question, this could be the possible answer and i hope you understand and interpret it correctly:
<span>[Integrate [0, 1/2] xcos(pi*x
let u=x so that du=dx
and v=intgral cos (xpi)dx
v=(1/pi)sin(pi*x)
integration by parts
uv-itgral[0,1/2]vdu just plug ins
(1/pi)sinpi*x]-(1/pi)itgrlsin(pi*x)dx from 0 to 1/2
(1/pi)x sinpi*x - (1/pi)[-(1/pi) cos pi*x] from 0 to 1/2
=(1/2pi)+(1/pi^2)[cos pi*x/2-cos 0]
=1/2pi - 1/2pi^2
=(pi-2)/2pi^2 ans</span>
The answer is c=5 hope this helps
Plug in the points and see if y and x are equal to each other.
(2,3)
y= x-1
3= 2-1
3= 1 (not the solution)
y=3x
3=3*3
3=9 (not the solution)
y=x+1
3=2+1
3=3 (solution) We can check to make sure.
y=-3x
3=-3*3
3=-9 (not the solution)
y=x+1 <em>is the answer.
</em>
I hope this helps!
~kaikers
Answer:
x = y = 2√2
Step-by-step explanation:
Find the diagram attached
To get the unknown side x and y, we need to use the SOH CAH TOA identity
Opposite side = x
Adjacent = y
Hypotenuse = 4
Sin theta = opposite/hypotenuse
sin 45 = x/4
x = 4 sin 45
x = 4 * 1/√2
x = 4 * 1/√2 * √2/√2
x = 4 * √2/√4
x = 4 * √2/2
x = 2√2
Similarly;
cos theta = adjacent/hypotenuse
cos 45 = y/4
y = 4cos45
y = 4 * 1/√2
y = 4 * 1/√2 * √2/√2
y = 4 * √2/√4
y = 4 * √2/2
y = 2√2
