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qaws [65]
2 years ago
8

Need some help on this

Mathematics
1 answer:
Schach [20]2 years ago
8 0

Hi there!

The two angles are alternate-interior angles, so:
∠A ≅ ∠B

6x + 18 = x + 93

Solve for x. Subtract x from both sides:

5x + 18 = 93

Subtract 18 from both sides:

5x = 75

Divide both sides by 5.

x = 75/5 = 15°

Now, solve for angle B by plugging in this value into the equation.

∠B = 15 + 93 = <u>108°</u>

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Answer:

The answer is

<h2>\frac{3c}{4e}</h2>

Step-by-step explanation:

<h3>\frac{9 {c}^{3}d {e}^{2}  }{12 {c}^{2} d {e}^{3} }</h3>

To solve the fraction reduce the fraction with d

That's we have

<h2>\frac{9 {c}^{3}  {e}^{2} }{12 {c}^{2} {e}^{3}  }</h2>

Next simplify the expression using the rules of indices to simplify the letters in the fraction

<u>For c </u>

Since they are dividing we subtract the exponents

We have

<h2>{c}^{3}  \div  {c}^{2}  =  {c}^{3 - 2}  = c^{1}  = c</h2>

<u>For </u><u>e</u>

<h2>e^{2}  \div  {e}^{3}  = e^{2 - 3}  =  {e}^{ - 1}  =  \frac{1}{e}</h2>

Substituting them into the expression we have

<h2>\frac{9c}{12e}</h2>

Reduce the fraction by 3

We have the final answer as

<h2>\frac{3c}{4e}</h2>

Hope this helps you

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