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rusak2 [61]
3 years ago
6

Use this graph of f to find f(6).

Mathematics
2 answers:
Ludmilka [50]3 years ago
6 0

Answer: I will help you once you add a graph in the comments of this post

Step-by-step explanation:

Arlecino [84]3 years ago
5 0

Answer:once u post it I’ll help

Step-by-step explanation:

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mr. kelly pays $12,564 a year for rent. his rent constant a constant each month. which eqation represents the amount he pays per
Luden [163]
He pays 1047 ur welcome ur welcome ur welcome ur welcom ur welcome ur welcom
7 0
3 years ago
An air traffic controller spots two airplanes at the same altitude converging to a point as they fly at right angles to each oth
sattari [20]
They are traveling at right angles to each other so we can say one is traveling north to south and the other west to east.  Then we can say that there positions, y and x are:

y=150-600t  x=200-800t

By using the Pythagorean Theorem we can find the distance between these two planes as a function of time:

d^2=y^2+x^2, using y and x from above

d^2=(150-600t)^2+(200-800t)^2

d^2=22500-180000t+360000t^2+40000-320000t+640000t^2

d^2=1000000t^2-500000t+62500

d=√(1000000t^2-500000t+6250)

So the rate of change is the derivative of d

dd/dt=(1/2)(2000000t-500000)/√(1000000t^2-500000t+6250)

dd/dt=(1000000t-250000)/√(1000000t^2-500000t+6250)

So the rate depends upon t and is not a constant, so for the instantaneous rate you would plug in a specific value of t...

...

To find how much time the controller has to change the airplanes flight path, we only need to solve for when d=0, or even d^2=0...

1000000t^2-500000t+62500=0

6250(16t^2-8t+1)=0

6250(16^2-4t-4t+1)=0

6250(4t(4t-1)-1(4t-1))=0

6250(4t-1)(4t-1)=0

6250(4t-1)^2=0

4t-1=0

4t=1

t=1/4 hr

Well technically, the controller has t<1/4 because at t=1/4 impact will occur :)


7 0
3 years ago
Consider the function f(x)= 1-|x-1|+|x+1| for -3&lt;x&lt;3. Recall that the absolute function can be represented as a piece wise
Kruka [31]
By the definition for the absolute value,

|x-1|=\begin{cases}x-1&\text{for }x\ge1\\-(x-1)&\text{for }x
|x+1|=\begin{cases}x+1&\text{for }x\ge-1\\-(x+1)&\text{for }x

So for the compound function f(x)=1-|x-1|+|x+1|, there are three intervals to consider. What happens when x? when -1\le x? when x\ge1?

You have

f(x)=\begin{cases}1-(-(x-1))+(-(x+1))=-1&\text{for }x
8 0
4 years ago
What is the value of x in the equation ?2.5(6x-4)=10 4(1.5 0.5x)
MA_775_DIABLO [31]
<span>2.5<span>(<span><span>6x</span>−4</span>)</span></span>=<span><span><span><span><span>(10)</span><span>(4)</span></span><span>(1.5)</span></span><span>(0.5)</span></span><span>x

</span></span><span><span><span><span>(2.5)</span><span>(<span>6x</span>)</span></span>+<span><span>(2.5)</span><span>(<span>−4</span>)</span></span></span>=<span><span><span><span><span>(10)</span><span>(4)</span></span><span>(1.5)</span></span><span>(0.5)</span></span>x</span></span>(Distribute)<span><span><span><span>15x</span>+</span>−10</span>=<span>30x
</span></span><span><span><span>15x</span>−10</span>=<span>30<span>x


</span></span></span><span><span><span><span>15x</span>−10</span>−<span>30x</span></span>=<span><span>30x</span>−<span>30x</span></span></span><span><span><span>−<span>15x</span></span>−10</span>=<span>0

</span></span><span><span><span><span>−<span>15x</span></span>−10</span>+10</span>=<span>0+10</span></span><span><span>−<span>15x</span></span>=<span>10
</span></span><span><span><span>−<span>15x</span></span><span>−15</span></span>=<span>10<span>−15</span></span></span><span>x=<span><span>−2</span><span>3
</span></span></span>Answer:<span>x=<span><span>−2</span><span>3</span></span></span>

<span>

</span><span>


</span>
3 0
3 years ago
What is the mathematical shape made by each net
Bumek [7]
A) cylinder
b) triangular pyramid
5 0
3 years ago
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