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3 years ago

Can somebody help me

Mathematics

2 answers:

Effectus [21]3 years ago

8 0

Answer:

30°

Step-by-step explanation:

because this needs 180 angle so 150 (20+130)

180-150 equals 30

sammy [17]3 years ago

5 0

Answer:

30°

a full triangle is 180° so to find the missing angle you must add the two given angles (20°+130°) then take the answer away from 180° (180°-150°)

hence your answer is 30°

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In Exercises 45–48, let f(x) = (x - 2)2 + 1. Match the function with its graph

MA_775_DIABLO [31]

Answer:

45) The function corresponds to graph A

46) The function corresponds to graph C

47) The function corresponds to graph B

48) The function corresponds to graph D

Step-by-step explanation:

We know that the function f(x) is:

$f(x)=(x-2)^{2}+1$

45)

The function g(x) is given by:

$g(x)=f(x-1)$

using f(x) we can find f(x-1)

$g(x)=((x-1)-2)^{2}+1=(x-3)^{2}+1$

If we take the derivative and equal to zero we will find the minimum value of the parabolla (x,y) and then find the correct graph.

$g(x)'=2(x-3)$

$2(x-3)=0$

$x=3$

Puting it on g(x) we will get y value.

$y=g(3)=(3-3)^{2}+1$

$y=g(3)=1$

Then, the minimum point of this function is (3,1) and it corresponds to (A)

46)

Let's use the same method here.

$g(x)=f(x+2)$

$g(x)=((x+2)-2)^{2}+1$

$g(x)=(x)^{2}+1$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2x$

$0=2x$

$x=0$

Evaluatinf g(x) at this value of x we have:

$g(0)=(x)^{2}+1$

$g(0)=1$

Then, the minimum point of this function is (0,1) and it corresponds to (C)

47)

Let's use the same method here.

$g(x)=f(x)+2$

$g(x)=(x-2)^{2}+1+2$

$g(x)=(x-2)^{2}+3$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2(x-2)$

$0=2(x-2)$

$x=2$

Evaluatinf g(x) at this value of x we have:

$g(2)=(2-2)^{2}+3$

$g(2)=3$

Then, the minimum point of this function is (2,3) and it corresponds to (B)

48)

Let's use the same method here.

$g(x)=f(x)-3$

$g(x)=(x-2)^{2}+1-3$

$g(x)=(x-2)^{2}-2$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2(x-2)$

$0=2(x-2)$

$x=2$

Evaluatinf g(x) at this value of x we have:

$g(2)=(2-2)^{2}-2$

$g(2)=-2$

Then, the minimum point of this function is (2,-2) and it corresponds to (D)

I hope it helps you!

8 0

2 years ago

Find a point on the graph of the function y=f(x)+3

Fudgin [204]

In the general case, it is (x, y+3), where y = f(x).

5 0

3 years ago

Simplify the expressions plz help

Sophie [7]

Alright, so the answer for:

3) is 3v + 4

6 0

3 years ago

The figure shows a carpeted room. How many square feet of the room is carpeted?

alukav5142 [94]

Answer:

Step-by-step explanation:

So split it into two shapes. Two rectangles.

Rectangle 1 = 4 * 5 = 20

Rectangle 2 = 2 * 10 = 20

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2 years ago

Read 2 more answers

4b−3.2=3(2b−4) can you plz solve

evablogger [386]

Answer:

4b-3.2=6b-12

12-3.2=6b -4b

8.8=2b

b=8.÷2

b=4.4

3 0

3 years ago