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makvit [3.9K]
3 years ago
14

What is the approximate distance between two points with coordinates (3,5) and (-4, -8)? Round your answer to the nearest hundre

dth.​
Mathematics
2 answers:
ludmilkaskok [199]3 years ago
7 0

Answer:

15 (rounded) 14.7 (not rounded)

Step-by-step explanation:

WITCHER [35]3 years ago
3 0

Answer:

15

Step-by-step explanation:

use the distance formula

d = √((x2-x1)^2 + (y2-y1)^2)

d = √((-4-3)^2 + (-8-5)^2)

d = √((-7)^2 + (-13)^2)

d = √(49 + 169)

d = √218

d = 14.76 ≅ 15

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ElenaW [278]

Answer:

It is an isosceles triangle.

Angle R = 65 degrees

If side RT = 1 then sides SR and ST = 1.1831

Step-by-step explanation:

6 0
4 years ago
BRAINLEIST ASAP! PLEASE HELP ME FAST! :)
Arturiano [62]

Answer:

Lines c and b, f and d (option b)

Step-by-step explanation:

To prove whether the lines satisfy the condition of being a transversal to another, let's prove one of the conditions wrong, and thus the answer -

Option 1:

Here lines a and b do not correspond to one another provided they are both transversals, thus don't act as transversals to one another, they simply intersect at a given point.

Option 2:

All conditions are met, lines c and b correspond with one another such that b is a transversal to both c and d. Lines f and d correspond with one another such that f is a transversal to both d and c.

Option 3:

Lines c and d are both not transversals, thus clearly don't act as transversals to one another.

Option 4:

Lines c and d are both not transversals, thus clearly don't act as transversals to one another.

8 0
3 years ago
(-3,5) is located in
Aleksandr-060686 [28]

It is located in the 2nd quadrant.

(x,y) - 1st quadrant

(-x,y) - 2nd quadrant

(-x,-y) - 3rd quadrant

(x,-y) - 4th quadrant

8 0
3 years ago
Read 2 more answers
A simple random sample (SRS) of 150 is taken from a population with a 0.6 proportion of success. An independent SRS of 250 is ta
Virty [35]

Answer:

SE_{\hat p_1 -\hat p_2}= \sqrt{\frac{0.6(1-0.6)}{150}+\frac{0.3(1-0.3)}{250}}= 0.0494

Step-by-step explanation:

For this case we have the following data:

n_1 =150 represent the random sample 1 selected

\hat p_1 =0.6 represent the proportion of success for the sample 1 selected

n_2 =250 represent the random sample 2 selected

\hat p_2 =0.3 represent the proportion of success for the sample 2 selected

We know for this case that we can use the normal approximation since for both cases we have:

n_1 p_1  =90 \geq 10, n_1 (1-p_1)=60 \geq 10

n_2 p_2  =75 \geq 10, n_2 (1-p_2)=175 \geq 10

We have the randomization condition and we assume that the two samples are <10% of the entire population size.

So then we can use the following distribution for the proportions:

p \sim N( \hat p, \sqrt{\frac{\hat p (1-\hat p)}{n}})

For this case we want to find the distribution for the difference of these two proportions and we have this:

p_1 -p_2 \sim N (\hat p_1 -\hat p_2 , \sqrt{\frac{\hat p_1 (1-\hat p_1)}{n_1} +\frac{\hat p_2 (1-\hat p_2)}{n_2}})

So then the dtandard deviation would be given by:

SE_{\hat p_1 -\hat p_2}= \sqrt{\frac{0.6(1-0.6)}{150}+\frac{0.3(1-0.3)}{250}}= 0.0494

4 0
4 years ago
Read 2 more answers
5(4x+1)(1x+1) <br> how do i solve?
BARSIC [14]

Answer:

5(4x + 1)(1x + 1) \\  =5(4x + 1)(x + 1) \\  = 20x(x + 1) + 5(x + 1) \\  = 20 {x}^{2}  + 20 + 5x + 5 \\  = 20 {x}^{2}  + 5x + 25

Hope it helps!

4 0
3 years ago
Read 2 more answers
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