Consider rectangular box with
- length x units (x≥0);
- width 3 units;
- height (8-x) units (8-x≥0, then x≤8).
The volume of the rectangular box can be calculated as
In your case,
Note that maximal possible value of the height can be 8 units (when x=0 - minimal possible length) and the minimal possible height can be 0 units (when x=8 - maximal possible length).
From the attached graph you can see that the greatest x-intercept is x=8, then the height will be minimal and lenght will be maximal.
Then the volume will be V=0 (minimal).
Answer: correct choices are B (the maximum possible length), C (the minimum possible height)
Answer:
B. No, this distribution does not appear to be normal
Step-by-step explanation:
Hello!
To observe what shape the data takes, it is best to make a graph. For me, the best type of graph is a histogram.
The first step to take is to calculate the classmark`for each of the given temperature intervals. Each class mark will be the midpoint of each bar.
As you can see in the graphic (2nd attachment) there are no values of frequency for the interval [40-44] and the rest of the data show asymmetry skewed to the left. Just because one of the intervals doesn't have an observed frequency is enough to say that these values do not meet the requirements to have a normal distribution.
The answer is B.
I hope it helps!
Answer:56
Step-by-step explanation:do 180-68, then divide by 2(because the x angles are equal to each other.
Answer:
1.97-20= -18.03
20-1.97= 18.03
Step-by-step explanation:subtract the numbers from each other.
Assuming the life sized dolphin is 12 ft long, what we want to know is what factor do you multiply 12 ft by to get 3.5 inches so converting this to an equation gives: 12*f=3.5 solving for f gives f=3.5/12=.29166...The units on the factor are inches/foot.
So to get the size if anything linear in the small scale you just multiply it's dimension in the full scale by f.
