I believe it b but dont take my word for it if you dont believe me
m∠5 = 142°
Solution:
Line l and m are parallel.
<em>Sum of the adjacent angles in a straight line is 180°.</em>
⇒ 38° + m∠7 = 180°
⇒ m∠7 = 180° – 38°
⇒ m∠7 = 142°
∠5 and ∠7 are corresponding angles.
<em>If two parallel lines are cut by a transversal, then the corresponding angles on the same side are congruent.</em>
⇒ ∠5 ≅ ∠7
⇒ m∠5 = m∠7
⇒ m∠5 = 142°
Therefore m∠5 = 142°.
Hello There!
The correct answer is Figure made up of two or more basic shapes.
Hope This Helps You!
Good Luck :)
Your answer is a rise over run and the line is in a negative slope
Answer:
The dilation scale factor is
.
Step-by-step explanation:
The image is the dilated form of its preimage if and only if the following conditions are observed:
1) ![K' = \alpha_{1} \cdot K](https://tex.z-dn.net/?f=K%27%20%3D%20%5Calpha_%7B1%7D%20%5Ccdot%20K)
2) ![T' = \alpha_{2} \cdot T](https://tex.z-dn.net/?f=T%27%20%3D%20%5Calpha_%7B2%7D%20%5Ccdot%20T)
3) ![P' = \alpha_{3} \cdot P](https://tex.z-dn.net/?f=P%27%20%3D%20%5Calpha_%7B3%7D%20%5Ccdot%20P)
4) ![J' = \alpha_{4} \cdot J](https://tex.z-dn.net/?f=J%27%20%3D%20%5Calpha_%7B4%7D%20%5Ccdot%20J)
5) ![\alpha_{1} = \alpha_{2} = \alpha_{3} = \alpha_{4}](https://tex.z-dn.net/?f=%5Calpha_%7B1%7D%20%3D%20%5Calpha_%7B2%7D%20%3D%20%5Calpha_%7B3%7D%20%3D%20%5Calpha_%7B4%7D)
If we know that
,
,
,
,
,
,
and
, then the coefficients are, respectively:
,
,
, ![\alpha_{4} = \frac{1}{2}](https://tex.z-dn.net/?f=%5Calpha_%7B4%7D%20%3D%20%5Cfrac%7B1%7D%7B2%7D)
As
, we conclude that the dilation scale factor applied in the preimage is equal to
.