Answer:-26.25
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given:
KL ║ NM ,
LM = 45
m∠M = 50°
KN ⊥ NM
NL ⊥ LM
Find: KN and KL
1. Consider triangle NLM. This is a right triangle, because NL ⊥ LM. In this triangle,
LM = 45
m∠M = 50°
So,
Also
(angles LNM and M are complementary).
2. Consider triangle NKL. This is a right triangle, because KN ⊥ NM . In this triangle,
(alternate interior angles)
(angles KNL and KLN are complementary).
So,
and
A. The circumference of the circle:
C = 2 π r = 2 * 3.14 * 8 = 50.24 cm
B. The area of the circle:
A = π r² = 3.14 * 8² = 200.96 cm²
C. The area of the square:
Let's calculate first the side of the square. It is equal to 2r = 2*8=16 cm
The area of the square is:
16*16 = 256 cm²
Hope that helps.
We know that
[area of a regular hexagon]=6*[area of one <span>equilateral triangle]
</span>210.44=6*[area of one equilateral triangle]
[area of one equilateral triangle]=210.44/6-----> 35.07 cm²
[area of one equilateral triangle]=b*h/2
h=7.794 cm
b=2*area/h------> b=2*35.07/7.794------>b= 9 cm
the length side of a regular hexagon is 9 cm
<span>applying the Pythagorean theorem
</span>r²=h²+(b/2)²------>r²=7.794²+(4.5)²------> r²=81--------> r=9 cm
<span>this last step was not necessary because the radius is equal to the hexagon side------> (remember the equilateral triangles)
</span>
the answer is
the radius is 9 cm
