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Nostrana [21]
2 years ago
10

Given the preimage and image,find the dilation scale factor.​

Mathematics
1 answer:
Oliga [24]2 years ago
7 0

Answer:

The dilation scale factor is \frac{1}{2}.

Step-by-step explanation:

The image is the dilated form of its preimage if and only if the following conditions are observed:

1) K' = \alpha_{1} \cdot K

2) T' = \alpha_{2} \cdot T

3) P' = \alpha_{3} \cdot P

4) J' = \alpha_{4} \cdot J

5) \alpha_{1} = \alpha_{2} = \alpha_{3} = \alpha_{4}

If we know that K = (2, 0), K' = (1, 0), T = (3, 0), T' = (1.5,0), P = (1, 5), P' = (0.5, 2.5), J = (0, 3) and J' = (0, 1.5), then the coefficients are, respectively:

\alpha_{1} = \frac{1}{2}, \alpha_{2} = \frac{1}{2}, \alpha_{3} = \frac{1}{2}, \alpha_{4} = \frac{1}{2}

As \alpha_{1} = \alpha_{2} = \alpha_{3} = \alpha_{4}, we conclude that the dilation scale factor applied in the preimage is equal to \frac{1}{2}.

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\qquad \qquad\huge \underline{\boxed{\sf Answer}}

Here's the solution ~

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\qquad \sf  \dashrightarrow \: h {}^{2}  =  {8}^{2}  +  {6}^{2}

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Now, let's find the asked values ~

\qquad \sf  \dashrightarrow \:  \sin(x) =  \dfrac{opposite \: side}{hypotenuse}

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For Cos y :

\qquad \sf  \dashrightarrow \:  \cos(y) =  \dfrac{adjcant \: side}{hypotenuse}

\qquad \sf  \dashrightarrow \:  \cos(y)   = \dfrac{6}{10}

\qquad \sf  \dashrightarrow \:  \cos(y)   = \dfrac{3}{5}  \: or \: 0.6 \: units

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