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Nostrana [21]
3 years ago
10

Given the preimage and image,find the dilation scale factor.​

Mathematics
1 answer:
Oliga [24]3 years ago
7 0

Answer:

The dilation scale factor is \frac{1}{2}.

Step-by-step explanation:

The image is the dilated form of its preimage if and only if the following conditions are observed:

1) K' = \alpha_{1} \cdot K

2) T' = \alpha_{2} \cdot T

3) P' = \alpha_{3} \cdot P

4) J' = \alpha_{4} \cdot J

5) \alpha_{1} = \alpha_{2} = \alpha_{3} = \alpha_{4}

If we know that K = (2, 0), K' = (1, 0), T = (3, 0), T' = (1.5,0), P = (1, 5), P' = (0.5, 2.5), J = (0, 3) and J' = (0, 1.5), then the coefficients are, respectively:

\alpha_{1} = \frac{1}{2}, \alpha_{2} = \frac{1}{2}, \alpha_{3} = \frac{1}{2}, \alpha_{4} = \frac{1}{2}

As \alpha_{1} = \alpha_{2} = \alpha_{3} = \alpha_{4}, we conclude that the dilation scale factor applied in the preimage is equal to \frac{1}{2}.

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What is the volume of the rectangular prism?
Gnesinka [82]

Answer:

Option (4)

Step-by-step explanation:

Volume of a rectangular prism is given by the formula,

Volume = Length × Width × Height

From the picture attached,

Length of the prism = 5 cm

Width of the prism = 3\frac{3}{4} = \frac{15}{4} cm

Height of the prism = 8\frac{1}{2} = \frac{17}{2} cm

Volume of the given prism = \frac{5}{1} × \frac{15}{4} × \frac{17}{2}

                                             = \frac{5\times 15\times 17}{1\times 4\times 2}

                                             = \frac{1275}{8}

                                             = 159\frac{3}{8} cm³

Therefore, Option (4) is the correct option.

3 0
3 years ago
Solve the equation.
chubhunter [2.5K]

Answer:

b=-115.072

Step-by-step explanation:

So yeah Thats it guys

7 0
3 years ago
Read 2 more answers
Find the vectors T, N, and B at the given point. r(t) = < t^2, 2/3t^3, t >, (1, 2/3 ,1)
maxonik [38]

Answer with Step-by-step explanation:

We are given that

r(t)=< t^2,\frac{2}{3}t^3,t >

We have to find T,N and B at the given point t > (1,2/3,1)

r'(t)=

\mid r'(t) \mid=\sqrt{(2t)^2+(2t^2)^2+1}=\sqrt{(2t^2+1)^2}=2t^2+1

T(t)=\frac{r'(t)}{\mid r'(t)\mid}=\frac{}{2t^2+1}

Now, substitute t=1

T(1)=\frac{}{2+1}=\frac{1}{3}

T'(t)=\frac{-4t}{(2t^2+1)^2} +\frac{1}{2t^2+1}

T'(1)=-\frac{4}{9}+\frac{1}{3}

T'(1)=\frac{1}{9}=

\mid T'(1)\mid=\sqrt{(\frac{-2}{9})^2+(\frac{4}{9})^2+(\frac{-4}{9})^2}=\sqrt{\frac{36}{81}}=\frac{2}{3}

N(1)=\frac{T'(1)}{\mid T'(1)\mid}

N(1)=\frac{}{\frac{2}{3}}=

N(1)=

B(1)=T(1)\times N(1)

B(1)=\begin{vmatrix}i&j&k\\\frac{2}{3}&\frac{2}{3}&\frac{1}{3}\\\frac{-1}{3}&\frac{2}{3}&\frac{-2}{3}\end{vmatrix}

B(1)=i(\frac{-4}{9}-\frac{2}{9})-j(\frac{-4}{9}+\frac{1}{3})+k(\frac{4}{9}+\frac{2}{9})

B(1)=-\frac{2}{3}i+\frac{1}{3}j+\frac{2}{3}k

B(1)=\frac{1}{3}

5 0
3 years ago
Determine the value of x using a trigonometric ratio.
gladu [14]

We have a known hypotenuse, but unknown opposite side. Use the sine ratio to tie the two together to be able to solve for x.

sin(angle) = opposite/hypotenuse

sin(50) = x/6.5

6.5*sin(50) = x

x = 6.5*sin(50)

x = 4.97928888027336 make sure your calculator is in degree mode

x = 4.98

Answer is choice B

6 0
3 years ago
PLS HELP DUE SOON SHOW YOUR WORK!
Vladimir79 [104]

9514 1404 393

Answer:

  • 615.8 square feet
  • 9 truckloads

Step-by-step explanation:

The area of the circular ring is given by the formula ...

  A = πr²

where r is the radius, or half the diameter.

  A = π(14 ft)² = 196π ft² ≈ 615.752 ft²

The area of the training area is about 615.8 square feet.

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The number of truckloads of dirt required for coverage will be ...

  (615.8 ft²)/(75 ft²/truckload) ≈ 8.21 truckloads

Since the dirt comes only in whole truckloads, Hilary needs 9 truckloads.

8 0
3 years ago
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