Answer:
The x-intercept is x = -2, and the graph approaches a vertical asymptote at x = -3.
Step-by-step explanation:
The given graph is a transformed logarithm function.
The graph is obtained by shifting the parent function three units left.
The vertical asymptote is now

The x-intercept is where the graph intersect the x-axis, which is x=-2
Therefore the last option is correct.
<span>3x- 1/9 y=18
</span><span>3x- 1/9(27) =18
3x - 3 = 18
3x = 21
x = 7
hope it helps</span>
The algebraic expression for the mathematical statement given as 4 more than the difference of 12 and a number j is 4 + 12 - j
<h3>How to determine the arithmetic expression?</h3>
The mathematical statement is given as:
4 more than the difference of 12 and a number j
4 more than means 4 +.
So, we have:
4 + the difference of 12 and a number j
the difference of 12 and a number j means 12 - j
So, we have
4 + 12 - j
Hence, the algebraic expression for the mathematical statement given as 4 more than the difference of 12 and a number j is 4 + 12 - j
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A and D is what you're looking for.
8 classes x 20 students per class = 160 students
8 classes x 2 chaperones per class = 16 chaperones
Total people on the buses . . . . . . . . . . 176 people
The expression for the number of buses needed is:
Number of buses = 1 + (the greatest integer in 176/25)
That's because if there are any people left over after the
last full bus of 25, they will need one more bus.
Unfortunately for the school's budget, this group needs
7 full buses carrying 25 people in each, and one bus
carrying one single person in it.
A possible solution to the problem would be to find somebody
who is certified as a bus driver and willing to work two jobs
on the field trip, to act as one of the chaperones. Then they
might get away with only 7 buses.
If this doesn't work, then they can just forget about the whole
idea of 25 on a bus. Loading them to capacity doesn't help,
because it still leaves one person without a ride. They might
as well just put one class and their chaperones on each of the
8 buses, and give each load a little bit of room to spread out.
If there's one student out of 160 who is sick or otherwise doesn't
show up on field-trip day, then they can squeeze everybody into
7 fully-loaded buses. But since they had to reserve 8 buses and
drivers, they'll probably have to pay for the eighth one anyway.