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2 years ago

Please help me 10 points

Mathematics

1 answer:

Oksana_A [137]2 years ago

7 0

$7\dfrac{2}{9}-3\dfrac{5}{6}=7\dfrac{2\cdot2}{9\cdot2}-3\dfrac{5\cdot3}{6\cdot3}=7\dfrac{4}{18}-3\dfrac{15}{18}\\\\=6\dfrac{22}{18}-3\dfrac{15}{18}=3\dfrac{7}{18}$

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2 years ago

Indicate the general rule for the arithmetic sequence with a3 = -12 and a8 = -37

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Answer:

The general rule is $a_n = -2 - 5(n-1)$

Step-by-step explanation:

Arithmetic sequence:

In an arithmetic sequence, the difference between consecutive terms is always the same, and this difference is called common difference.

The general rule of an arithmetic sequence is given by:

$a_{n} = a_1 + (n-1)d$

In which $a_1$ is the first term and d is the common difference.

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First we find the common difference. So

$a_n = a_m + (n-m)d$

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$d = -\frac{25}{5}$

$d = -5$

$a_n = a_1 - 5(n-1)$

Finding the first term:

$a_n = a_1 - 5(n-1)$

Since $a_3 = -12$

$a_n = a_1 - 5(n-1)$

$a_3 = a_1 - 5(3-1)$

$a_1 = a_3 + 10 = -12 + 10 = -2$

So the general rule is:

$a_n = a_1 - 5(n-1)$

$a_n = -2 - 5(n-1)$

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Answer:

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To answer this all you need to do is divide 120 by 50

120/50
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2 years ago