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Andru [333]
3 years ago
14

How do you write a quadratic equation in standard form?

Mathematics
1 answer:
Lemur [1.5K]3 years ago
3 0

Answer:

  • Powers of the variable descending left to right
  • right side of the equal sign is 0

Step-by-step explanation:

For some constants a, b, and c, the standard form* is ...

  ax^2 + bx + c = 0

___

It is nice if the leading coefficient (a) is positive, but that is not required.

The main ideas are that ...

  • Powers of the variable are descending
  • All of the non-zero terms are on the left side of the equal sign
  • Like terms are combined

_____

* This is the <em>standard form</em> for a quadratic. For other kinds of equations, when the expression is equal to zero, this would be called "general form."

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10 added to the difference between t and 8
Eddi Din [679]

Answer:

(t-8)+10

Step-by-step explanation:

6 0
3 years ago
After grabbing some food from the cafeteria, Ray trips causing his food to go up in the air before hitting the ground. The parab
Dahasolnce [82]

The maximum height of the tray is 1.8 meters and the tray is in the air for 2 seconds

<h3>The maximum height of the tray</h3>

The distorted information (i.e. the function) in the question is:

h(t) = -0.2t^2 + 0.4t + 1.6

Differentiate the function

h'(t) = -0.4t + 0.4

Set to 0

-0.4t + 0.4 = 0

Subtract 0.4 from both sides

-0.4t = -0.4

Divide by -0.4

t = 1

Substitute t = 1 in h(t) = -0.2t^2 + 0.4t + 1.6

h(1) = -0.2(1)^2 + 0.4(1) + 1.6

Evaluate

h(1) = 1.8

Hence, the maximum height of the tray is 1.8 meters

<h3>Time spent in the air</h3>

In (a), we have:

t = 1

This represents the time to reach the maximum height.

The time spent in the air is:

T = 2t

This gives

T = 2 * 1

T = 2

Hence, the tray is in the air for 2 seconds

Read more about quadratic functions at:

brainly.com/question/11535666

#SPJ1

7 0
2 years ago
a photograph is printed in the center of a piece of paper measuring 7 cm by (x + 8) cm. The photo measures 5 cm by (x +6) cm . T
Nadusha1986 [10]

The paper is 7 cm by (x + 8) cm.

A photo is 5 cm by (x + 6) cm, and is printed in the middle of the paper.

The area of the border/space around the photo is 50 cm².


To find the area of the border around the photo, you find the area of the paper and subtract it by the area of the photo.


The area of the paper:

A = 7 · (x + 8)


The area of the photo:

A = 5 · (x + 6)


Your equation to find the area of the border around the photo is:

(7 · (x + 8)) - (5 · (x + 6)) = A

[area of paper - area of photo = area of border]


Since you know the area of the border, you can plug it in:

(7 · (x + 8)) - (5 · (x + 6)) = 50


Multiply the 7 into (x + 8), and multiply the 5 into (x + 6)

(7x + 56) - (5x + 30) = 50


Distribute/multiply the - to (5x + 30)

7x + 56 - 5x - 30 = 50


Combine like terms

2x + 26 = 50


Subtract 26 on both sides

2x = 24


Divide 2 on both sides


x = 12

7 0
3 years ago
Let f(x) = x ^ 2 and g(x) = x - 3 . Evaluate (g?f)(0).
nignag [31]

Answer:

g(f(0))=-3

Step-by-step explanation:

we have

f(x)=x^{2}

g(x)=x-3

we know that

(g o f)(x)=g(f(x))

substitute the variable x in the function g(x) by the function f(x)

so

g(f(x))=x^{2}-3

Evaluate g(f(0))

For x=0

g(f(0))=0^{2}-3

g(f(0))=-3

5 0
4 years ago
Will give brainlesr please help im 25% blind
My name is Ann [436]

Answer:

Option D

Step-by-step explanation:

the height of the first rectangle ( 30 ) over the height of the other rectangle     ( 3 )  is 30/3 and equals 10

the length of the first rectangle ( 60 ) over the length of the second rectangle  ( 6 )  is 60/6 and equals 10

the ratio of the sides of both rectangles are equivalent therefore the are similar

3 0
3 years ago
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