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3 years ago

How do you write a quadratic equation in standard form?

Mathematics

1 answer:

Lemur [1.5K]3 years ago

3 0

Answer:

Powers of the variable descending left to right
right side of the equal sign is 0

Step-by-step explanation:

For some constants a, b, and c, the standard form* is ...

ax^2 + bx + c = 0

___

It is nice if the leading coefficient (a) is positive, but that is not required.

The main ideas are that ...

Powers of the variable are descending
All of the non-zero terms are on the left side of the equal sign
Like terms are combined

_____

* This is the <em>standard form</em> for a quadratic. For other kinds of equations, when the expression is equal to zero, this would be called "general form."

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What is the sign of B + A?

Fed [463]

The sign would be NEGATIVE

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3 years ago

Which of the following terms do not represent like terms 9x^2 and 5x 2x and 7y 8 and 107 a^2 and 2a

ASHA 777 [7]

Answer:

2x and 7y, because they have different variables.

Step-by-step explanation:

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4 years ago

The sale price of ground beef at a local grocery store is $1.49 for the 1st pound and 1.09 for each additional pound which funct

bixtya [17]

Y=1.09(x-1)+1.49 where y is cost and x is in pounds we could further operate:

y=1.09x-1.09+1.49

y=1.09x+0.4 (note that the domain is x≥1)

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4 years ago

Write a system of linear inequalities so the points (1, 2) and (4, -3) are solutions of the system, but the point (-2, 8) is not

Verizon [17]

Answer: $\left \{ {{y\leq -\frac{5}{3}x + \frac{11}{3}} \atop {y < 8}} \right$

<u>Step-by-step explanation:</u>

(1, 2) and (4, -3)

First, find the slope (m): $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

m = $\frac{-3-2}{4-1}$

= $-\frac{5}{3}$

Next, choose ONE of the points and input the point and slope into the Point-Slope formula: y - y₁ = m(x - x₁)

y - 2 = $-\frac{5}{3}$ (x - 1)

y - 2 = $-\frac{5}{3}x$ + $\frac{5}{3}$

y = $-\frac{5}{3}x$ + $\frac{11}{3}$

Then, determine which inequality symbol will result in (-2, 8) being False (since it is not a solution):

y ___ $-\frac{5}{3}x$ + $\frac{11}{3}$

8 ___ $-\frac{5}{3}(-2)$ + $\frac{11}{3}$

8 ___ $\frac{1}{3}$

8 > $\frac{1}{3}$

so ≤ makes the statement False

⇒ y ≤ $-\frac{5}{3}x$ + $\frac{11}{3}$

****************************************************************

If you need a "system" of inequalities, then you need another equation.

There are infinite possibilities. Graph the points to see what works.

y < 8 or x > -2 are two examples.

---> I just realized that the system can be simpler than what I did above:

$\left \{ {{x>-2} \atop {y < 8}} \right$

4 0

3 years ago

Evaluate this exponential expression 3 x (5+4)^2-4^2

mr_godi [17]

Answer:

227

Step-by-step explanation:

To get the answer, first we open all the parentheses

3*9^2-4^2

then solve the exponents

3*81-16

multiply

243-16

So our answer is

227

(plz give brainliest)

3 0

3 years ago