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gogolik [260]
3 years ago
15

Tommy earned $76 in interest after 5 years on a principal of $400. Jane earned $82 in interest after 2 years on a principal of $

1,000. Which bank would you rather use? Why?
Mathematics
1 answer:
UkoKoshka [18]3 years ago
7 0
Jane’s bank because the rate of Jane’s bank is 4.1%, which is faster than Tommy’s bank’s rate, which is 3.8%.
You might be interested in
I dont understand I need help
gregori [183]

Answer:

7.4825 km or 7.48 km (rounded to nearest hundredth)

Step-by-step explanation:

<u>Ranch's measurements rounded up to the nearest hundredth:</u>

1st measurement = \sqrt{60} = 7.75 km

2nd measurement = \frac{58}{8} = 7.25 km

3rd measurement = 7.3(recurring) = 7.33 km

4th measurement = 7\frac{3}{5} = 7.60

<u>The average of the four measurements is:</u>

(7.75 + 7.25 + 7.33 + 7.60) ÷ 4 = 7.4825 km or 7.48 km (rounded to nearest hundredth)

6 0
4 years ago
What is 5,000 in scientific notation?
eimsori [14]
5.0x103

Bolded=exponent
4 0
3 years ago
An object is heated to 100°. It is left to cool in a room that
stepladder [879]

Answer:

Step-by-step explanation:

Use Newton's Law of Cooling for this one.  It involves natural logs and being able to solve equations that require natural logs.  The formula is as follows:

T(t)=T_{1}+(T_{0}-T_{1})e^{kt} where

T(t) is the temp at time t

T₁ is the enviornmental temp

T₀ is the initial temp

k is the cooling constant which is different for everything, and

t is the time (here, it's in minutes)

If we are looking first for the temp after 20 minutes, we have to solve for the k value.  That's what we will do first, given the info that we have:

T(t) = 80

T₁ = 30

T₀ = 100

t = 5

k = ?

Filling in to solve for k:

80=30+(100-30)e^{5k} which simplifies to

50=70e^{5k} Divide both sides by 70 to get

\frac{50}{70}=e^{5k} and take the natural log of both sides:

ln(\frac{5}{7})=ln(e^{5k})

Since you're learning logs, I'm assuming that you know that a natural log and Euler's number, e, "undo" each other (just like taking the square root of something squared).  That gives us:

-.3364722366=5k

Divide both sides by 5 to get that

k = -.0672944473

Now that we have a value for k, we can sub that in to solve for T(20):

T(20)=30+(100-30)e^{-.0672944473(20)} which simplifies to

T(20)=30+70e^{-1.345888946}

On your calculator, raise e to that power and multiply that number by 70:

T(20)= 30 + 70(.260308205) and

T(20) = 30 + 18.22157435 so

T(20) = 48.2°

Now we can use that k value to find out when (time) the temp of the object cools to 35°:

T(t) = 35

T₁ = 30

T₀ = 100

k = -.0672944473

t = ?

35=30+100-30)e^{-.0672944473t} which simplifies to

5=70e^{-.0672944473t}

Now divide both sides by 70 and take the natural log of both sides:

ln(\frac{5}{70})=ln(e^{-.0672944473t}) which simplifies to

-2.63905733 = -.0672944473t

Divide to get

t = 39.2 minutes

3 0
3 years ago
Which of the following solutions solves the system?
gavmur [86]

Answer:

i think its

Step-by-step explanation:

D

5 0
3 years ago
How does 15.050 compare to 15.500
Varvara68 [4.7K]

15.050 < 15.500

notice that 500 is more than 50... so hope this helps a little bit !!!

:)

6 0
3 years ago
Read 2 more answers
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