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Cerrena [4.2K]
3 years ago
15

Problem

Mathematics
1 answer:
Stels [109]3 years ago
7 0

Answer:

The maximum speed of Hal's airplane in still air is:

v= 250\ miles/h

The speed of the wind

c = 50\ miles/h

Step-by-step explanation:

Remember that the velocity v equals the distance d between time t.

v=\frac{d}{t}  and t*v=d

The distance that Hal travels when traveling with the wind is:

(2\ hours)(v + c) = 600 miles

Where v is the speed of Hal and c is the wind speed.

The distance when traveling against the wind is:

(3\ hours)(v-c) = 600 miles

Now we solve the first equation for v

(2)(v + c) = 600

2v + 2c = 600

2v= 600-2c

v= 300-c

Now we substitute the value of v in the second equation and solve for c

3((300-c)-c) = 600

3(300-2c) = 600

900-6c = 600

-6c = 600-900

-6c = -300

6c = 300

c = 50\ miles/h

Then:

v= 300-(50)

v= 250\ miles/h

The maximum speed of Hal's airplane in still air is:

v= 250\ miles/h

The speed of the wind

c = 50\ miles/h

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