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asambeis [7]
2 years ago
11

What is a reasonable estimate for the solution? O (1,-3/4) O (-3/4,1) O (-1,3/4) O (3/4,-1)​

Mathematics
1 answer:
Zina [86]2 years ago
6 0

Answer:

See Explanation

Step-by-step explanation:

Your question is incomplete, as the equations or graph or table(s) were not given.

However, I'll give a general way of solving this.

Take for instance, the equations are:

y = \frac{4}{3}x - 1

y = \frac{2}{3}x - \frac{1}{2}

To do this, we start by equating both equations.

y = y

i.e.

\frac{4}{3}x - 1= \frac{2}{3}x - \frac{1}{2}

Collect Like Terms

\frac{4}{3}x - \frac{2}{3}x= 1 - \frac{1}{2}

Take LCM

\frac{4x- 2x}{3}= \frac{2 - 1}{2}

\frac{2x}{3}= \frac{1}{2}

Cross Multiply

2x * 2 = 3 * 1

4x = 3

Make x the subject

x = \frac{3}{4}

Substitute 3/4 for x in y = \frac{4}{3}x - 1

y = \frac{4}{3} * \frac{3}{4} - 1

y = 1 - 1

y = 0

Hence:

(x,y) = (\frac{3}{4},0)

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Answer:

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Na atmosfera,a temperatura diminui cerca de1 grau a cada 200 m de afastamento da superficie terrestre.Se a temperatura na superf
Alenkinab [10]

Responder:

- 30 ° C

Explicação passo a passo:

Dado que :

A temperatura diminui 1 ° para cada 200 m afastados da superfície terrestre

Temperatura na superfície da terra = 20 ° C

Temperatura atmosférica a uma altura de 10 km de. Superfície Terrestre :

Queda de temperatura para uma altura de 10 km de distância;

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1 * (10000/200)

1 * 50

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Portanto ;

Temperatura da superfície terrestre - 50 ° C

20 ° C - 50 ° C

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4 0
2 years ago
You buy some beads and string from a student on campus to make a bracelet for yourself. You valued the materials at $11 but were
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Answer: the surplus is 12$

Step-by-step explanation:

You only need to calculate what you bought it for and what you sold it for

You bought the materials for eight dollars and sold the materials/bracelet for 20, 20-8 means you have a surplus of 12 dollars

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3 years ago
(THIS ONE FIRST)The volume of a cube is 27 cubic inches. Which expression represents s, the length of a side of the cube?
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Answer:

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Step-by-step explanation:

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