2² - y - 5 = 0
Evaluate the power.
4 - y - 5 = 0
Calculate the sum or difference.
-1 - y = 0
Move constant to the right side and change its sign.
-y = 1
Change the signs on both sides of the equation.
y = -1
<span>The graph you plotted is the graph of f ' (x) and NOT f(x) itself. </span>
Draw a number line. On the number line plot x = 3 and x = 4. These values make f ' (x) equal to zero. Pick a value to the left of x = 3, say x = 0. Plug in x = 0 into the derivative function to get
f ' (x) = (x-4)(6-2x)
f ' (0) = (0-4)(6-2*0)
f ' (0) = -24
So the function is decreasing on the interval to the left of x = 3. Now plug in a value between 3 and 4, say x = 3.5
<span>f ' (x) = (x-4)(6-2x)
</span><span>f ' (3.5) = (3.5-4)(6-2*3.5)
</span>f ' (3.5) = 0.5
The function is increasing on the interval 3 < x < 4. The junction where it changes from decreasing to increasing is at x = 3. This is where the min happens.
So the final answer is C) 3
Answer:
No
Step-by-step explanation:
Assuming that you put the wrong sign for the second equation if you plug (2,7) into the two equations it only works for one equation.
Answer:
153
Step-by-step explanation:
y/3=51
Multiply each side by 3
y/3 *3 = 51*3
y = 153
