Solve for x for x: x+2y=2
x+2y +-2y=2+-2y (add -2y on both sides.)
x=-2y+2
Substitute : -2y+2 for x in
4x-y=4:
4(-2y+2)-y=4
-9y+8=4 Simplify both sides of the equation.
-9y+8+-8=4+-8 Add -8 to both sides.
-9y=-4
-9/-9=-4-9 Divide both sides by -9
y=4/9
Substitute 4/9 for y in
x=-2y+2
x=-2(4/9)+2
x=10/9
y=4/9,x=10/9
Answer:
1) solution is y = -7
2.) DNE
3.) Solution is y = -2
Step-by-step explanation:
1.) 2+3 = y + 12
Add the LHS and make y the subject of formula
5 = y + 12
Y = 5 - 12
Y = - 7
The solution of the equation is - 7
2.) 2 + 13 = 1 +8
Since there is no unknown variable and the sum of the numbers in the left hand side ( LHS ) is not equal to the sum of the numbers in the right hand side ( RHS ), it will be concluded that there is no solution in the equation.
3.) y - 7 = 2 - 11
Sum the RHS and make y the subject of formula
Y - 7 = -9
Y = -9 + 7
Y = -2
The solution of the equation is -2
<span>No, it doesn't. To find out if it's a right angled triangle, we use Pythagorean triple. It states that the square of the hypotenuse (the longest side) is equal to the sum of the squares of the opposite and adjacent sides. Obviously, the longest side, which is our hypotenuse is 24. So we want to find out whether the square of our hypotenuse is equal to the sum of the squares of the other two sides i. e 13 and 21.
24^ 2 = 576 ; 13^2 = 169 ; 21^2 = 441;
So is 576 = 169 + 441. An emphatic No: hence the triangle isn't right angled since it doesn't satisfy pythagorean triple.. A^2 is not equal to B^2 + C^2 where a is the hypotenuse and b and c the opposite and adjacent sides.</span>
