Answer:
3 ≤ x ≤ 7 or x is between 3 and 7, inclusive
Step-by-step explanation:
Eira's graph probably resembled the diagram below.
The domain is the set of all possible x-values that will make a function work.
x can take any value from 3 to 7.
The domain is [3, 7] or 3 ≤ x ≤ 7.
Answer:
6x + 14
Step-by-step explanation:
Area = side x side
Factor the quadratic:
2x^2 +10x / +1x +5
2x(x+5) 1 (x+5)
(2x + 1) (x+5)
^These are your two sides
Perimeter =2L + 2W
(2(2x+1)) + (2(x+5))
4x+4+2x+10 = final answer 6x + 14
Since x - 3 < 0 for -2 < x < 3, |x-3| = -(x-3)
Since x + 2 > 0 for -2 < x < 3, |x+2| = x+2
Since x - 5 < 0 for -2 < x < 3, |x-5| = -(x-5).
So y = -(x-3) + (x+2) -(-(x-5)) = 3 - x + x + 2 + x - 5 = x.
y = x, if -2 < x < 3.
Work the information to set inequalities that represent each condition or restriction.
2) Name the
variables.
c: number of color copies
b: number of black-and-white copies
3)
Model each restriction:
i) <span>It
takes 3 minutes to print a color copy and 1 minute to print a
black-and-white copy.
</span><span>
</span><span>
3c + b</span><span>
</span><span>
</span><span>ii) He needs to print
at least 6 copies ⇒
c + b ≥ 6</span><span>
</span><span>
</span><span>iv) And must have
the copies completed in
no more than 12 minutes ⇒</span>
3c + b ≤ 12<span />
4) Additional restrictions are
c ≥ 0, and
b ≥ 0 (i.e.
only positive values for the number of each kind of copies are acceptable)
5) This is how you
graph that:
i) 3c + b ≤ 12: draw the line 3c + b = 12 and shade the region up and to the right of the line.
ii) c + b ≥ 6: draw the line c + b = 6 and shade the region down and to the left of the line.
iii) since c ≥ 0 and b ≥ 0, the region is in the
first quadrant.
iv) The final region is the
intersection of the above mentioned shaded regions.v) You can see such graph in the attached figure.
Answer:
86
X.06
_____
516
+ 0000
_________
05.16
Step-by-step explanation:
