Answer: 4 kilograms of dough and will continue preparing 1 kilogram of dough every hour.
Step-by-step explanation:
Answer:
y=2e^(−x)cosx−e^(−x)sinx
Satisfies the equation
Step-by-step explanation:
Answer:
y=2e^(−x)cosx−e^(−x)sinx
y = e^(-x)[2cosx - sinx]
Find y' and y" using product law
y' = -e^(-x)[2cosx - sinx] + e^(-x)[-2sinx - cosx]
y' = -e^(-x)[2cosx - sinx + 2sinx + cosx]
y' = -e^(-x)[3cosx + sinx]
y" = e^(-x)[3cosx + sinx] - e^(-x)[-3sinx + cosx]
y" = e^(-x)[3cosx - cosx + sinx + 3sinx]
y" = e^(-x)[2cosx + 4sinx]
y" + 2y' + 2y
e^(-x)[2cosx + 4sinx] - 2e^(-x)[3cosx + sinx] +2e^(-x)[2cosx - sinx]
e^(-x)[4sinx - 2sinx - 2sinx + 2cosx - 6 cosx + 4cosx]
= e^(-x) × 0
= 0
I think I understand 3 but not the rest of them
Answer:
x = 70
Step-by-step explanation:
The total interior angle in a square, even with not a perfect square, adds to 360
Set your formula up as
360 = (x+15) + x + 115 + 90
360 - 115 - 90 - 15 = 2x
140 = 2x
140/2 = x
70 = x
Answer:
cubic meter of clay will be used to create all the pyramids
Step-by-step explanation:
The remaining part of the question is given in the attached file
Solution
The total clay used is equal to the sum of volumes of two triangular and three rectangular pyramids.
For Rectangular Pyramid,
Volume of three rectangular pyramids
Substituting the given values in above equation, we get -
cubic centimeter
For triangular Pyramid,
Volume of two triangular pyramids
cubic centimeter
Total clay used = Volume of 3 rectangular pyramid + volume of 2 triangular pyramid 
Cubic centimeter
