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Cerrena [4.2K]
3 years ago
14

In 2000 the population of a city was 588292 people. in 2002 the population of the city increased to 599656, what is the populati

on in 2008
Mathematics
1 answer:
slamgirl [31]3 years ago
7 0
The population in 2008 is <span>635,082. This is true given that we follow the 1.93% increase in population every two years. The rate was derived from the increase of 588,292 (year 2000) to 599,656 (year 2002). The computation is:

((599,656 - 588,292) / 588,292) * 100 = 1.93%

Applying the rate every two years, here's what get:

</span><span> <span> </span><span> 2000: <span>588,292
</span></span></span><span> <span> </span><span> 2002:<span> 599,656
</span></span></span><span> <span> </span><span> 2004:<span> 611,240
</span></span></span><span> <span> </span><span> 2006: <span>623,047
</span></span></span><span> <span> </span><span><span> 2008: <span>635,082</span></span></span></span>
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3 years ago
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Answer:

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Answer in point-slope form, you can rearrange this into the form which you need.

Step-by-step explanation:

recall that the general point-slope form of a linear equation looks like :

(y - y₁) = m(x - x₁)

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simply substitute this info into the general equation above

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4 0
3 years ago
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stich3 [128]

To solve this problem you must apply the proccedure shown below:

1. You have that Jim drove the car 2,718.3 miles for a total mileage of 87,416.

2. Then, to calculate the mileage before last month, you only need to substract the total mileage given in the exercise above and the mileage drove last month, as following:

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Therefore, the answer is: 84,697.7 miles.

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