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Cerrena [4.2K]
2 years ago
14

In 2000 the population of a city was 588292 people. in 2002 the population of the city increased to 599656, what is the populati

on in 2008
Mathematics
1 answer:
slamgirl [31]2 years ago
7 0
The population in 2008 is <span>635,082. This is true given that we follow the 1.93% increase in population every two years. The rate was derived from the increase of 588,292 (year 2000) to 599,656 (year 2002). The computation is:

((599,656 - 588,292) / 588,292) * 100 = 1.93%

Applying the rate every two years, here's what get:

</span><span> <span> </span><span> 2000: <span>588,292
</span></span></span><span> <span> </span><span> 2002:<span> 599,656
</span></span></span><span> <span> </span><span> 2004:<span> 611,240
</span></span></span><span> <span> </span><span> 2006: <span>623,047
</span></span></span><span> <span> </span><span><span> 2008: <span>635,082</span></span></span></span>
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We can then put the above slope and the point (-1,4) into the formula:

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