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trasher [3.6K]
3 years ago
8

The table below shows the size of nine families selected at random from two neighborhoods in a large city: Family Size (in numbe

r of people) Neighborhood A 4 4 5 5 5 5 5 5 6 Neighborhood B 6 5 5 4 4 3 4 2 4 Which neighborhood appears to have a bigger family size? Explain your answer using two or three sentences. Make sure to use facts to support your answer
asap
Mathematics
1 answer:
barxatty [35]3 years ago
4 0
So the first thing we need to do is find the average family size. 4+4+5+5+5+5+5=29/7= 4.1428

6+5+5+4+4+3+4+2+4= 4.1111111111111
So Neighborhood A has the biggest families
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plz help whats the answer to this question !!! calculate the mass of a gold bar that is 18.00cm long, 9.21cm wide, and 4.45cm hi
erik [133]

We have to find the mass of the gold bar.

We have gold bar in the shape of a rectangular prism.

The length, width, and the height of the gold bar is 18.00 centimeters, 9.21 centimeters, and 4.45 centimeters respectively.

First of all we will find the volume of the gold bar which is given by the volume of rectangular prism:

Volume of the gold bar = length \times width\times height

Plugging the values in the equation we get,

Volume of the gold bar =18.00 \times 9.21 \times 4.45= 737.721cm^3

Now that we have the volume we can find the mass by using the formula,

Mass= density \times volume

The density of the gold is 19.32 grams per cubic centimeter. Plugging in the values of density and volume we get:

Mass = 19.32\times 737.721=14252.769 grams

So, the mass of the gold bar is 14252.769 grams

7 0
3 years ago
(4x + 4)(ax – 1) – x2 +4
Oksana_A [137]

Answer:

b=-3

Step-by-step explanation:

If the expression simplifies to bx that means the x^{2} terms and the constant terms must be cancel out.

Simplify it first.

(4x+4)(ax-1)-x^{2} +4\\=(4ax^{2} -4x+4ax-4)-x^{2} +4\\=4ax^{2} -x^{2} -4x+4ax-4+4\\=4ax^{2} -x^{2} -4x+4ax

We know –4 + 4 will cancel out. If we simplify this expression to only an x term, then the x^{2} terms should be cancelled. Therefore, we say that 4ax^2 – x^2 = 0.

4ax^{2} -x^{2} =0\\x^{2} (4a-1)=0\\4a-1=0\\4a=1\\a=\frac{1}{4}

If we put a = ¼, then we can find the value of b:

=4(\frac{1}{4} )x^{2} -x^{2} -4x+4(\frac{1}{4} )x\\=x^{2} -x^{2} -4x+x\\ (cancel out x^{2} terms)\\

=-3x

bx=-3x\\      if the  expression is equivalent to bx

Therefore, b = –3.

8 0
3 years ago
Peter babysits his sister on Monday and Friday. He babysits for his neighbor 40% of the days Monday through Friday. He babysits
ExtremeBDS [4]
It’s was right 3 days
4 0
2 years ago
Read 2 more answers
A gallon of paint covers 400 square feet. How many square feet will 2 3/8 gallons of paint cover. How do you solve this problem.
PSYCHO15rus [73]

Answer:

Hey there!

1 gallon=400 square feet

2 3/8 gallon= 400 (2 3/8) square feet

2 3/8 gallon= 950 square feet.

Let me know if this helps :)

5 0
3 years ago
Suppose a student started with 139.0 mg of trans-cinnamic acid, 463 mg of pyridinium tribromide, and 2.45 mL of glacial acetic a
Sliva [168]

Answer:

0.2889 g  brominated product

64.6 %

Step-by-step explanation:

This is a bromination chemical reaction of an alkene  and we are asked to calculate the theoretical and percent yield. Thus to solve it we have to perform a calculation based on the balanced chemical reaction.

The pyridinium tribromide is used as a generator of molecular bromine in situ, and bromine will add to the double bond in trans-cinnamic acid so we know the reaction occur in a one to one mole fashion.

trans-cinnamic acid + pyridinium  tribromide ⇒ 2,3-dibromo-3-                          

                                                                             phenylpropanoic acid

Molar weight  trans-cinnamic acid  =  148.16 g/mol

mass trans-cinnamic acid  = 139.0 mg x  1g/1000 mg = 0.139 g

# mol trans-cinnamic acid =  0.139 g / 148 g/mol = 9.38 x 10⁻⁴ mol

Since our reaction is 1 mol trans-cinnamic acid  produces 1 mol 2,3-dibromo-3-phenylpropanoic acid, it follows that the theoretical yield is:

1 mol 2,3-dibromo-3-phenylpropanoic acid /  trans-cinnamic acid x 9.38 x 10⁻⁴ mol trans-cinnamic acid  

=  9.38 x 10⁻⁴ mol  2,3-dibromo-3-phenylpropanoic acid

In grams the the theoretical yield is:

molar mass  2,3-dibromo-3-phenylpropanoic acid = 307.97 g/mol

The theoretical mass  2,3-dibromo-3-phenylpropanoic acid:

=   9.38 x 10⁻⁴ mol  2,3-dibromo-3-phenylpropanoic acid x 307.97 g/mol

=   0.2889 g

% yield = mass experimental/mass theoretical

= 0.1866 g /  0.2889 g x 100 = 64.6 %

4 0
2 years ago
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