
Substitute this into the parabolic equation,

We're told the line
intersects
twice, which means the quadratic above has two distinct real solutions. Its discriminant must then be positive, so we know

We can tell from the quadratic equation that
has its vertex at the point (3, 6). Also, note that

and

so the furthest to the right that
extends is the point (5, 2). The line
passes through this point for
. For any value of
, the line
passes through
either only once, or not at all.
So
; in set notation,

Answer:
A. 17
B. 16
Step-by-step explanation:
F(5)
5 > 2 so you plug the 5 into 3x+2
F(-2)
-5 < -2 < 2 so you plug the -2 into (x-2)^2
Answer:
Answer:
Step-by-step explanation:
Slope of a line 2x+3y=6 is -2/3
So line passing through (0,4) has same slope because both are parallel
From slope intercept form we have
Y-y1 =m(x-1)
Y-4= -2/3(x-0)
3Y-12 = -2x
3Y+2x = 12
Which is required equation of a line.
Step-by-step explanation:
Answer:
63
Step-by-step explanation:
Answer:
56/125
Step-by-step explanation: