Question

How can I evaluate this question?

Answer 1

$\bf \left(x^2-\cfrac{2}{\sqrt{x}}+1 \right)(\sqrt[3]{x}+3x-4)\quad \begin{cases} \frac{2}{\sqrt{x}}\implies \frac{2}{x^{\frac{1}{2}}}\implies 2x^{-\frac{1}{2}}\\\\ \sqrt[3]{x}\implies x^{\frac{1}{3}} \end{cases} \\\\\\ (x^2-2x^{-\frac{1}{2}}+1)(x^{\frac{1}{3}}+3x-4)$

$\bf \\\\\\ \begin{cases} x^2\cdot x^{\frac{1}{3}}+3x^3-4x^2\\\\ -2x^{-\frac{1}{2}}\cdot x^{\frac{1}{3}}-2x^{-\frac{1}{2}}\cdot 3x+2x^{-\frac{1}{2}}\cdot 4\\\\ +x^{\frac{1}{3}}+3x-4 \end{cases} \\\\\\ \begin{cases} x^{2+\frac{1}{3}}+3x^3-4x^2\\\\ -2x^{-\frac{1}{2}+\frac{1}{3}}-6x^{-\frac{1}{2}+1}+8x^{-\frac{1}{2}}\\\\ +x^{\frac{1}{3}}+3x-4 \end{cases}$

$\bf x^{\frac{7}{3}}+3x^3-4x^2-2x^{-\frac{1}{6}}-6x^{\frac{1}{2}}+8x^{-\frac{1}{2}}+x^{\frac{1}{3}}+3x-4 \\\\\\ \sqrt[3]{x^7}+3x^3-4x^2-\cfrac{2}{x^{\frac{1}{6}}}-6\sqrt{x}+\cfrac{8}{x^{\frac{1}{2}}}+\sqrt[3]{x}+3x-4 \\\\\\ x^2\sqrt[3]{x}+3x^3-4x^2-\cfrac{2}{\sqrt[6]{x}}-6\sqrt{x}+\cfrac{8}{\sqrt{x}}+\sqrt[3]{x}+3x-4$