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qaws [65]
3 years ago
9

How do you solve this

Mathematics
1 answer:
fiasKO [112]3 years ago
4 0
(((x + y) / 3) + (1 / x)) / (5 + (15 / x))
The best way is to make it one fraction.
Multiply by ((3x/3x) / (3x/3x)) to remove the other fractions.
((x(x + y)) + 3(1)) / (5(3x) + 3(15))
(x^2 + xy + 3) / (15x + 45)
Then factor to simplify
(x^2 + xy + 3) / (3(x + 15))



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goblinko [34]

f(9) is the x value, find where the line is in the y direction at x = 9

The line crosses y = 3 at x = 9

Answer:

f(9) = 3

8 0
2 years ago
1. Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial i
Katena32 [7]
Polynomial with real coefficients always has even number of complex roots. We know that one of them is 2 + 5i so the second one will be  2 - 5i and:

f(x)=\big(x-4\big)\big(x-(-8)\big)\big(x-(2+5i)\big)\big(x-(2-5i)\big)=\\\\=(x-4)(x+8)(x-2-5i)(x-2+5i)=\\\\=(x^2-4x+8x-32)(x^2-2x+5ix-2x+4-10i-5ix+10i-25i^2)\\\\=\big(x^2+4x-32\big)\big(x^2-4x+4-25\cdot(-1)\big)=\\\\=(x^2+4x-32)(x^2-4x+29)=\\\\=x^4-4x^3+29x^2+4x^3-16x^2+116x-32x^2+128x-928=\\\\=\boxed{x^4-19x^2+244x-928}

Answer B.
8 0
3 years ago
Read 2 more answers
Max measures the diagonal of a square room to be 32feet find the perimeter and area of the room round answers to the nearest ten
Rasek [7]
Hello!

To find the side length of a square with the diagonal you use the equation

a =  \sqrt{2}  \frac{d}{2}

a is side length
d is diagonal length

Put in the values you know

a =  \sqrt{2} *  \frac{32}{2}

Divide

a =  \sqrt{2} * 16

Multiply

a = 22.6

All the sides are 22.6 feet

Add all the sides

22.6 + 22.6 + 22.6 + 22.6 = 90.4

The answer is 90.4

Hope this helps!
3 0
3 years ago
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umka21 [38]

The answer is 32

hope this helps! :)

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3 years ago
PLEASE HURRY 10 POINTS What is the solution to the equation 3(2x+5)=3x+4x
Lerok [7]

Answer:

D x=15

Step-by-step explanation:

3(2x+5)=3x+4x

Distribute the 3

6x +15 = 3x+4x

Combine like terms

6x+15 = 7x

Subtract 6x from each side

6x+15 -6x = 7x-6x

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6 0
2 years ago
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