The answer is: 50.5
Solution:
3.03 x 100 = 303
303 ÷ 6 = 50.5
120 would be the perimeter to this problem.
Option C:
![\sum_{n=1}^{5} 3(0.2)^{n-1}=3.75](https://tex.z-dn.net/?f=%5Csum_%7Bn%3D1%7D%5E%7B5%7D%203%280.2%29%5E%7Bn-1%7D%3D3.75)
Solution:
Given expression:
![\sum_{n=1}^{5} 3(0.2)^{n-1}](https://tex.z-dn.net/?f=%5Csum_%7Bn%3D1%7D%5E%7B5%7D%203%280.2%29%5E%7Bn-1%7D)
Summation means sum of the numbers.
Put n = 1 to 5 and sum all the numbers.
![\sum_{n=1}^{5} 3(0.2)^{n-1}](https://tex.z-dn.net/?f=%5Csum_%7Bn%3D1%7D%5E%7B5%7D%203%280.2%29%5E%7Bn-1%7D)
![=3(0.2)^{1-1}+3(0.2)^{2-1}+3(0.2)^{3-1}+3(0.2)^{4-1}+3(0.2)^{5-1}](https://tex.z-dn.net/?f=%3D3%280.2%29%5E%7B1-1%7D%2B3%280.2%29%5E%7B2-1%7D%2B3%280.2%29%5E%7B3-1%7D%2B3%280.2%29%5E%7B4-1%7D%2B3%280.2%29%5E%7B5-1%7D)
![=3(0.2)^{0}+3(0.2)^{1}+3(0.2)^{2}+3(0.2)^{3}+3(0.2)^{4}](https://tex.z-dn.net/?f=%3D3%280.2%29%5E%7B0%7D%2B3%280.2%29%5E%7B1%7D%2B3%280.2%29%5E%7B2%7D%2B3%280.2%29%5E%7B3%7D%2B3%280.2%29%5E%7B4%7D)
Using exponential rule:
, so that ![0.2^0=1](https://tex.z-dn.net/?f=0.2%5E0%3D1)
![=3(1)+0.6+0.12+0.024+0.0048](https://tex.z-dn.net/?f=%3D3%281%29%2B0.6%2B0.12%2B0.024%2B0.0048)
![=3.7488](https://tex.z-dn.net/?f=%3D3.7488)
= 3.75
![\sum_{n=1}^{5} 3(0.2)^{n-1}=3.75](https://tex.z-dn.net/?f=%5Csum_%7Bn%3D1%7D%5E%7B5%7D%203%280.2%29%5E%7Bn-1%7D%3D3.75)
Option C is the correct answer.
Hence approximate value of
is 3.75.
Answer:
Answer - -5
Step-by-step explanation:
Answer:
6x -2y
Step-by-step explanation:
4x - 2y + 2x
Combine like terms
4x +2x - 2y
6x -2y