Question

When solving the system of equations 3x−3y=1 and −2x+4y=2 algebraically, a good first step is to:

Answer 1

Answer:

A. Multiply 3x−3y=1 by 2, and multiply −2x+4y=2 by 3.

Step-by-step explanation:

Given

$3x - 3y = 1$

$-2x+ 4y = 2$

Required

A good first step

A good first step is to eliminate x and this is done as follows:

Multiply $3x - 3y = 1$ by 2 (gotten from coefficient of x in the second equation)

Multiply $-2x+ 4y = 2$ by 3 (gotten from coefficient of x in the first equation)

This gives:

$6x - 6y = 2$

$-6x + 12y = 6$

Add both equations

$6x - 6x - 6y + 12y = 2 + 6$

$6y = 8$

$y = \frac{4}{3}$

Hence (a), is true