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n200080 [17]
3 years ago
12

Which ratios correctly compare bananas to apples, as shown in the picture ( 6 apples in a circle and 1 banana in the center ) ch

eck all that apply.... Pls help
Mathematics
2 answers:
Licemer1 [7]3 years ago
5 0

Answer:

6:1

Step-by-step explanation:

There are 6 apples t o1 banana

(This is all i can do would have been easier with picture)

cupoosta [38]3 years ago
3 0

Answer:

B , C ,D

Step-by-step explanation:

i got it right on edge

hope this helped <3

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Use the diagram to complete the statement.
Dima020 [189]

Answer:

∠FJH ≅ ∠BJA

Step-by-step explanation:

From the image we can see that the only congruent relation ∠FJH has is with ∠BJA which is due to these angles being vertically opposite

So, ∠FJH and ∠BJA are vertically opposite and hence, congruent. We can say that ∠FJH ≅ ∠BJA

4 0
3 years ago
Una persona camina 7 kilómetros hacia el norte, después 3 kilómetros hacia el este y, luego, 3 kilómetros hacia el sur. ¿A qué d
qaws [65]

Answer:

La persona está a 5 kilómetros con respecto al punto de partida.

Step-by-step explanation:

Considérese que la dirección norte coincide con el semieje +y y que la dirección este coincide con el semieje +x. A continuación, obtenemos las formas vectoriales equivalentes de cada afirmación:

(i) Una persona camina 7 kilómetros hacia el norte:

\vec r_{1} = 7\,\hat{j}\,[km]

(ii) Después 3 kilómetros hacia el este:

\vec r_{2} = 3\,\hat{i}\,[km]

(iii) Y luego, 3 kilómetros hacia el sur:

\vec r_{3} = -3\,\hat{j}\,[km]

El vector resultante de desplazamiento se construye a partir de la siguiente suma de vectores:

\vec R = \vec r_{1}+\vec r_{2} + \vec r_{3} (1)

\vec R = 3\,\hat{i} + 4\,\hat{j}\,[km]

Asumiendo que la distancia coincide con el desplazamiento resultante, calculamos la distancia con respecto al punto de partida mediante el Teorema de Pitágoras:

\|\vec R\| = \sqrt{3^{2}+4^{2}}

\|\vec R\| = 5\,km

La persona está a 5 kilómetros con respecto al punto de partida.

3 0
3 years ago
The value of a three digit number if the tens digit is c, the hundreds digit is three less than the tens and the ones digit is 0
raketka [301]

Answer:690 580 470 360 250 140

Step-by-step explanation:

These digits are all numbers that the hundreds digit is three less than the tens digit, the ones digit is also zero

5 0
3 years ago
Please help (20 points)
Evgesh-ka [11]

35.\\V=\dfrac{\pi r^2h}{3}\ \ \ \ |\cdot3\\\\3V=\pi r^2h\ \ \ \ |:\pi r^2\\\\\boxed{h=\dfrac{3V}{\pi r^2}}

36.\\V=150\ m^3\\r=5\ m\\h=?\\\\\text{substitute}\\\\h=\dfrac{3\cdot150}{\pi\cdot5^2}=\dfrac{450}{25\pi}=\dfrac{18}{\pi}\approx\dfrac{18}{3}=6\ m\\\\Answer:\ The\ height\ is\ greater\ than\ a\ radius.

8 0
3 years ago
What’s the answer?and how do you get it
Kay [80]

the solid is made up of 2 regular octagons, 8 sides, joined up by 8 rectangles, one on each side towards the other octagonal face.

from the figure, we can see that the apothem is 5 for the octagons, and since each side is 3 cm long, the perimeter of one octagon is 3*8 = 24.

the standing up sides are simply rectangles of 8x3.

if we can just get the area of all those ten figures, and sum them up, that'd be the area of the solid.

\bf \textit{area of a regular polygon}\\\\ A=\cfrac{1}{2}ap~~ \begin{cases} a=apothem\\ p=perimeter\\[-0.5em] \hrulefill\\ a=5\\ p=24 \end{cases}\implies A=\cfrac{1}{2}(5)(24)\implies \stackrel{\textit{just for one octagon}}{A=60} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{\textit{two octagon's area}}{2(60)}~~+~~\stackrel{\textit{eight rectangle's area}}{8(3\cdot 8)}\implies 120+192\implies 312

7 0
3 years ago
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