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Softa [21]
3 years ago
6

The students at Kayla's school are forming teams of three students for a quiz bowl competition. Kayla is assuming that each memb

er of a team is equally likely to be male or female. She uses a coin toss (heads = female, tails = male) to simulate this probability. Here is Kayla's data from 50 trials of 3 coin tosses: thh tth tth tht thh htt hth hht hth tth tth hht hth tht tht tth tth thh thh htt tht thh tth hht hth thh tht tth hht thh hhh tth tth hth htt tht thh hhh htt thh htt ttt tht ttt thh hht hth htt hht hth According to this data, what is the experimental probability that a team will consist entirely of girls? 0.33 0.04 0.2 0.02
Mathematics
1 answer:
scZoUnD [109]3 years ago
5 0

There are 2 instances of hhh (all girls) in the 50 trials, so the experimental probability is 2/50 = 4/100 = 0.04.

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A car dealership pays $8,350 for a car. They Mark up the price by 17.4% to get the retail price. What is the retail price of the
olga55 [171]

A car dealership pays the sum of $8,350 for a car

The dealer mark up the car price by 17.4%

The retail price = Mark up percentage x original price of the car

Mark up = 17.4%

= 17.4 + 10

= 117.4%

Convert 117.4% to decimal

= 117.4/100

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The retail price of the car is $9,802.90

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What is the standard deviation of this data?
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3 years ago
(a) How many integers from 1 through 1,000 are multiples of 2 or multiples of 9?
DENIUS [597]

Answer:

(a)There are 500 integers from 1 through 1,000 are multiples of 2.

There are 111 integers from 1 through 1,000 are multiples of 9.

(b)0.611

Step-by-step explanation:

Given the set of Integers from 1 through 1000

The least multiple of 2 is 2 and the highest multiple of 2 in the interval is 1000.

To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 2,4,6,... is an Arithmetic Progression,

where first term, a =2, common difference, d =2

Nth term of an A.P,

U_n= a+(n-1)d\\1000=2+2(n-1)\\1000=2+2n-2\\1000=2n\\n=500

  • There are 500 integers from 1 through 1,000 are multiples of 2.

Similarly,

Given the set of Integers from 1 through 1000

The least multiple of 9 is 9 and the highest multiple of 9 in the interval is 999.

To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 9,18,27,... is an Arithmetic Progression,

where first term, a =9, common difference, d =9

Nth term of an A.P,

U_n= a+(n-1)d\\999=9+9(n-1)\\999=9+9n-9\\999=9n\\n=111

  • There are 111 integers from 1 through 1,000 are multiples of 9.

(b)Probability that an integer selected at random is a multiple of 2 or a multiple of 9.

There are a total of 1000 numbers between from 1 through 1,000

n(S)=1000

n(Multiples of 2)=500

n(Multiples of 9)=111

Therefore:

P(\text{Multiples of 9}) \:OR\: P(\text{Multiples of 2})=\frac{111}{1000} + \frac{500}{1000} \\=\frac{611}{1000} \\=0.611

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3 years ago
Simplify <br> Rewrite the expression in the form z^n<br><br> z^5•z^6= ______
gtnhenbr [62]

Answer:

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Step-by-step explanation:

This is it enjoy.

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3 years ago
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