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nikdorinn [45]
3 years ago
8

On which number line do the points represent negative 4 and 1 over 2 and +3?

Mathematics
1 answer:
Allushta [10]3 years ago
8 0
A because if you look t is on +3 and r is on -41/2
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Nine increased by a number
Alina [70]
increased: add/addition ( + ) \\ Number: z


9 + z \\ or \\ z + 9

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7 0
3 years ago
Indicate below wether the equation in the box is true or false 6/12= 1/3
Hatshy [7]

Answer:

False

Step-by-step explanation:

6/12 simplifies into 1/2 (six is half of twelve) and 1/2 does not equal 1/3.

You can also plug this into a calculator and see that 6/12=0.5 and 1/3=0.333

8 0
1 year ago
One stats class consists of 52 women and 28 men. Assume the average exam score on Exam 1 was 74 (σ = 10.43; assume the whole cla
Svetllana [295]

Answer:

(A) What is the z- score of the sample mean?

The z- score of the sample mean is 0.0959

(B) Is this sample significantly different from the population?

No; at 0.05 alpha level (95% confidence) and (n-1 =79) degrees of freedom, the sample mean is NOT significantly different from the population mean.

Step -by- step explanation:

(A) To find the z- score of the sample mean,

X = 75 which is the raw score

¶ = 74 which is the population mean

S. D. = 10.43 which is the population standard deviation of/from the mean

Z = [X-¶] ÷ S. D.

Z = [75-74] ÷ 10.43 = 0.0959

Hence, the sample raw score of 75 is only 0.0959 standard deviations from the population mean. [This is close to the population mean value].

(B) To test for whether this sample is significantly different from the population, use the One Sample T- test. This parametric test compares the sample mean to the given population mean.

The estimated standard error of the mean is s/√n

S. E. = 16/√80 = 16/8.94 = 1.789

The Absolute (Calculated) t value is now: [75-74] ÷ 1.789 = 1 ÷ 1.789 = 0.559

Setting up the hypotheses,

Null hypothesis: Sample is not significantly different from population

Alternative hypothesis: Sample is significantly different from population

Having gotten T- cal, T- tab is found thus:

The Critical (Table) t value is found using

- a specific alpha or confidence level

- (n - 1) degrees of freedom; where n is the total number of observations or items in the population

- the standard t- distribution table

Alpha level = 0.05

1 - (0.05 ÷ 2) = 0.975

Checking the column of 0.975 on the t table and tracing it down to the row with 79 degrees of freedom;

The critical t value is 1.990

Since T- cal < T- tab (0.559 < 1.990), refute the alternative hypothesis and accept the null hypothesis.

Hence, with 95% confidence, it is derived that the sample is not significantly different from the population.

6 0
3 years ago
Write the equation in point-slope form of the line that passes through the given point and has the given slope.
Setler79 [48]

Answer:

The First Option

Step-by-step explanation:

y - 7 = -1/4(x - 4)

6 0
2 years ago
Read 2 more answers
Do you multiply or divide to get the Answer for 11-22
allochka39001 [22]
It divide 11÷22=2 and if you subtract it will be 11-22=11.please give me a like.
4 0
3 years ago
Read 2 more answers
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