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boyakko [2]
3 years ago
8

PLEASE MAKE ANSWER CLEAR

Mathematics
1 answer:
kati45 [8]3 years ago
3 0
You'll have to solve simultaneously

let nickel be x, dime be y

x + y = 35 ... ( 1 )

5x + 10 y = 250
5 ( x + 2y ) = 250
x + 2y = 50 ... ( 2 )

in ( 1 )
x = 35 - y ( 3 )

sub ( 3 ) into ( 2 )
( 35 - y ) + 2y = 50
y = 15

sub y into ( 1 )
x + y = 35
x + 15 = 35
x = 20

therefore, Sandy has 20 nickels and 15 dimes
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allochka39001 [22]
Melissa is represented by variable m.
Josh is represented by variable j.
Chau is represented by variable c.

m+j+c= 148
c=4m
j=m+10

Substitute for c and j for the first equation.
m+(m+10)+4m=148
6m+10=148
6m=138
m=23

Plug the known m value in
j=23+10
j=33

c=4(23)
c=92

Final answer: Melissa=23 messages, Josh=33 messages, Chau=92 messages
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