Answer:
He could have shut off the power first and de-energize the circuits in order to prevent being electrocuted.
Explanation:
Electrical Safety is very important, <em>especially for those working in such hazardous situations. </em>Almost all our things in the society are electrically-operated, thus it even becomes relevant to have an idea on how we can prevent from obtaining an electrical shock or burns due to faulty electrical tools.
In the worker's scenario above, it is clear that he did not shut off the power at the circuit breaker panel. This is the most important thing that one must include in his plan when attempting to correct an electrical problem. You must find where the electrical switch, fuses and circuit breakers are at first. Once you find their location, you have to turn them off (even if the circuits are of low-voltage).<u> In order to make sure that they are really turned off, test the circuits first. This will help you ensure that they are, indeed, de-energized.</u>
voltage difference is the push that causes charges to flow from high to low areas.
Answer:
don't know exactly ..............
The dimensions of the smaller holding pens from the parameters given are; 96 ft and 31 ft
<h3>What dimensions will maximize the area?</h3>
From the complete question, if the side lengths of the big rectangle are x and y, then the expression for the area A is:
A = x*y
Then perimeter since we have 384 ft of fencing available is;
2x + 2y = 384
y = (384 - 2x)/2
y = 192 - x
Put 192 - x for y in area formula;
A = x(192 - x)
A = 192x - x²
Completing the square of this are equation gives;
A = 9216 - (x - 96)²
This means that A is maximum at x - 96 = 0
Thus, A is maximum when x = 96 ft
At A_max; y = 192 - 96 = 96 ft
Since the area of the bigger rectangle has been maximized, it means that we have also maximized the area of the smaller pens. Therefore its' dimensions will be;
x_small = 96 ft/3 = 31 ft
y_small = 96 ft
Read more about maximizing area at; brainly.com/question/9819619
