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torisob [31]
3 years ago
8

An assembly line inspector inspected 340 machine parts. 323 of the parts passed inspection. What percent of the machine parts di

d NOT pass inspection?
Mathematics
1 answer:
tester [92]3 years ago
6 0

Answer:

5% did not pass inspection

Step-by-step explanation:

Given

Inspected= 340

Passed = 323

Required

Determine the percentage of parts that didn't pass inspection.

First, we need to calculate the number of those that didn't pass inspection.

Failed = Inspected - Passed

Failed = 340 - 323

Failed = 17

Next, we calculate the percentage as follows:

\% = \frac{Failed}{Inspected} * 100\%

The above formula is derived by dividing the number of parts that didn't pass inspection by the total machine inspected, then multiplied by 100%

So:

\% = \frac{17}{340} * 100\%

\% = \frac{17 * 100\%}{340}

\% = \frac{1700\%}{340}

\% = 5\%

<em>5% did not pass inspection</em>

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Answer:

0.321 is the probability that their mean printing speed of the sample is greater than 17.99 ppm.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 17.39 ppm

Standard Deviation, σ = 4.25 ppm

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We are given that the distribution of printing speed is a bell shaped distribution that is a normal distribution.

Formula:  

z_{score} = \displaystyle\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}  

P(printing speed of the sample is greater than 17.99 ppm.)  

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