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torisob [31]
3 years ago
8

An assembly line inspector inspected 340 machine parts. 323 of the parts passed inspection. What percent of the machine parts di

d NOT pass inspection?
Mathematics
1 answer:
tester [92]3 years ago
6 0

Answer:

5% did not pass inspection

Step-by-step explanation:

Given

Inspected= 340

Passed = 323

Required

Determine the percentage of parts that didn't pass inspection.

First, we need to calculate the number of those that didn't pass inspection.

Failed = Inspected - Passed

Failed = 340 - 323

Failed = 17

Next, we calculate the percentage as follows:

\% = \frac{Failed}{Inspected} * 100\%

The above formula is derived by dividing the number of parts that didn't pass inspection by the total machine inspected, then multiplied by 100%

So:

\% = \frac{17}{340} * 100\%

\% = \frac{17 * 100\%}{340}

\% = \frac{1700\%}{340}

\% = 5\%

<em>5% did not pass inspection</em>

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qwelly [4]

Option D:

$y=\frac{5x-2}{x}

Solution:

Given function:

$y=\frac{-2}{x-5}

To find the inverse of the function.

<u>Inverse of a function:</u>

<em>If a function f(x) is mapping x to y, then the inverse function of f(x) maps y back to x.</em>

$y=\frac{-2}{x-5}

Interchange the variables x and y.

$x=\frac{-2}{y-5}

Now, solve for y.

Multiply both sides by (y - 5).

$x(y-5)=-\frac{2}{y-5}(y-5)

Cancel the common factors, we get

x(y-5)=-2

Divide by x on both sides.

$y-5=-\frac{2}{x}

Add 5 on both sides.

$y=-\frac{2}{x}+5

$y=-\frac{2}{x}+\frac{5}{1}

To make the denominator same, multiply the 2nd term by \frac{x}{x}.

$y=-\frac{2}{x}+\frac{5x}{x}

$y=\frac{-2+5x}{x}

$y=\frac{5x-2}{x}

Option D is the correct answer.

8 0
3 years ago
stion 1 OT 5A researcher recorded the number of swans and the number of ducks in a lake every month. Function s represents the n
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Given functions are

s(n)=2(1.1)^n+5_{}d(n)=4(1.08)^n+3

The total number of ducks and swans in the lake after n months can be determined by adding the functions s(n) and d(n).

t(n)=s(n)+d(n)

t(n)=(2(1.1)^n^{}+5)+(4(1.08)^n+3)

t(n)=2(1.1)^n+5+4(1.08)^n+3

t(n)=2(1.1)^n+4(1.08)^n+5+3

t(n)=2(1.1)^n+4(1.08)^n+8

Taking 2 as common, we get

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t(n)=2\lbrack(1.1)^n+2(1.08)^n+4\rbrack

8 0
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