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tia_tia [17]
3 years ago
5

Can someone please give me the answers

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
3 0

Answer:

1) 3

2)9

3)18

4)18k

5)18 and k

6)k/3

7)k

8)3

9)9 + k/3

10) 18k - 9

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The original price of the paper was $3.50

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6 0
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2605 rounded to the nearest hundred
Fittoniya [83]
It would round to 2600
8 0
2 years ago
Log(x-2)+log2=2logy<br>log(x-3y+3)=0​
In-s [12.5K]

Answer:

<h2>x = 4 and y = 2 or x = 10 and y = 4</h2>

Step-by-step explanation:

\left\{\begin{array}{ccc}\log(x-2)+\log2=2\log y&(1)\\\log(x-3y+3)=0&(2)\end{array}\right

===========================\\\text{DOMAIN:}\\\\x-2>0\to x>2\\y>0\\x-3y+3>0\to x-3y>-3\\=====================\\\\\text{We know:}\ \log_ab=c\iff a^c=b,\\\\\text{therefore}\ \log_ab=0\iff a^0=b\to b=1\\\\\text{From this we have}\\\\\log(x-3y+3)=0\iff x-3y+3=1\qquad\text{add}\ 3y\ \text{to both sides}\\\\x+3=3y+1\qquad\text{subtract 3 from both isdes}\\\\\boxed{x=3y-2}\qquad(*)\\\\\text{Substitute it to (1)}

\log(3y-2-2)+\log2=2\log(y)\qquad\text{use}\ \log_ab^n=n\log_ab\\\\\log(3y-4)+\log2=\log(y^2)\qquad\text{subtract}\ \log(y^2)\ \text{from both sides}\\\\\log(3y-4)+\log2-\log(y^2)=0\\\\\text{Use}\ \log_ab+\log_ac=\log_a(bc)\ \text{and}\ \log_ab-\log_ac=\log_a\dfrac{b}{c}\\\\\log\dfrac{(3y-4)(2)}{y^2}=0\qquad\text{use}\ \log_ab=0\Rightarrow b=1\\\\\dfrac{(3y-4)(2)}{y^2}=1\iff y^2=(3y-4)(2)\\\\\text{Use the distributive property}\ a(b+c)=ab+ac

y^2=(3y)(2)+(-4)(2)\\\\y^2=6y-8\qquad\text{subtract}\ 6y\ \text{from both sides}\\\\y^2-6y=-8\qquad\text{add 8 to both sides}\\\\y^2-6y+8=0\\\\y^2-2y-4y+8=0\\\\y(y-2)-4(y-2)=0\\\\(y-2)(y-4)=0\iff y-2=0\ \vee\ y-4=0\\\\\boxed{y=2\ \vee\ y=4}\in D

\text{Put the values of}\ y\ \text{to }\ (*):\\\\\text{for}\ y=2:\\\\x=3(2)-2\\\\x=6-2\\\\\boxed{x=4}\in D\\\\\text{for}\ y=4:\\\\x=3(4)-2\\\\x=12-2\\\\\boxed{x=10}\in D

4 0
2 years ago
Square root of y^2 times y^2
Galina-37 [17]
<span>Square root of y^2 = y
so
</span><span>Square root of y^2 times y^2 = y * y^2 = y^3

answer
y^3</span>
8 0
3 years ago
A shop has determined that the number of bottles of water they sell on a summer day is a function of the day’s high temperature,
Alik [6]

Answer:

  •          T=t+94

                 Where T is the hight temperature and t is the day

Explanation:

The table shows that every day the<em> High temperature, T (degrees F) </em>increases 1 unit.

Then, this is a linear function with slope = 1ºF / day.

You can use the point-slope equation to determine the <em>function of the high temperature:</em>

  • Point-slope equation:

       y-y_1=m(x-x_1)

  • Choose any point from the table and m = 1. I will use the first point (1,95)

  • m = 1
  • x₁ = 1
  • y₁ = 95

Substitute:

        y-95=1(x-1)\\\\y=x-1+95\\\\y=x+94

Make the variables  y = T, and x = t:

     T=t+94

4 0
3 years ago
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