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Ad libitum [116K]
3 years ago
13

Which choice could be the equation of a line parallel to the line represented by this equation y=2x-3

Mathematics
2 answers:
Finger [1]3 years ago
7 0
B) y=2x+7 
lines with the same slope are parallel lines
MaRussiya [10]3 years ago
5 0

Answer:

B y=2x+7

Step-by-step explanation:

A first order function, also called a line, has the following format:

y = ax + b

In which a is the angular coefficient and b is the linear coefficient.

Lines are said to be parallel if they have the same angular coefficient.

In this problem, we have that:

y = 2x - 3

This line has an angular coefficient of 2.

So, a parallel line to this line will have an angular coefficient of 2.

The correct answer is:

B y=2x+7

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The perimeter of a rectangular toddler play area is 100 feet. The length is 10 feet more than 3 times the width. Find the length
Mekhanik [1.2K]

Answer:

length and width = 40 and 10 ft.

Step-by-step explanation:

The perimeter of a rectangular toddler play area is 100 feet.

Perimeter = 2(length + width)

Let the width = w

The length is 10 feet more than 3 times the width. Length = 10+(3w)

now put the values

100 = 2(10+3w + w)

100 = 2w + 20 + 6w

100 = (2w + 6w) + 20

100 = 8w + 20

8w = 100 - 20

w = \frac{80}{8}

w = 10 feet.

Now Length = 10+ (3w)

                     = 10+( 3 × 10)

                     = 10 + 30

                     = 40 feet

Therefore, length = 40 feet and width = 10 feet

8 0
4 years ago
Find two power series solutions of the given differential equation about the ordinary point x=0: y''-xy=0
OleMash [197]

The following are the answers to the question presented. Please see the attached image below.

I am hoping that these answers have satisfied your queries and it will be able to help you in your endeavors, and if you would like, feel free to ask another question.

7 0
4 years ago
5x-y=-1 + -5x+3y=25 for two variable elimination quiz
MakcuM [25]

Answer:

(\frac{11}{5},12)

Step-by-step explanation:

The system is

5x-y=-1

-5x+3y=25

We the two equations to get:

5x+-5x+-y+3y=25+-1

We simplify t get

2y=24

We divide both sides by 2 to get:

y=12

We now substitute y=12 in to the top equation to get:

5x-12=-1

5x=11

x=\frac{11}{5}

6 0
3 years ago
1. cot x sec4x = cot x + 2 tan x + tan3x
Mars2501 [29]
1. cot(x)sec⁴(x) = cot(x) + 2tan(x) + tan(3x)
    cot(x)sec⁴(x)            cot(x)sec⁴(x)
                   0 = cos⁴(x) + 2cos⁴(x)tan²(x) - cos⁴(x)tan⁴(x)
                   0 = cos⁴(x)[1] + cos⁴(x)[2tan²(x)] + cos⁴(x)[tan⁴(x)]
                   0 = cos⁴(x)[1 + 2tan²(x) + tan⁴(x)]
                   0 = cos⁴(x)[1 + tan²(x) + tan²(x) + tan⁴(4)]
                   0 = cos⁴(x)[1(1) + 1(tan²(x)) + tan²(x)(1) + tan²(x)(tan²(x)]
                   0 = cos⁴(x)[1(1 + tan²(x)) + tan²(x)(1 + tan²(x))]
                   0 = cos⁴(x)(1 + tan²(x))(1 + tan²(x))
                   0 = cos⁴(x)(1 + tan²(x))²
                   0 = cos⁴(x)        or         0 = (1 + tan²(x))²
                ⁴√0 = ⁴√cos⁴(x)      or      √0 = (√1 + tan²(x))²
                   0 = cos(x)         or         0 = 1 + tan²(x)
         cos⁻¹(0) = cos⁻¹(cos(x))    or   -1 = tan²(x)
                 90 = x           or            √-1 = √tan²(x)
                                                         i = tan(x)
                                                      (No Solution)

2. sin(x)[tan(x)cos(x) - cot(x)cos(x)] = 1 - 2cos²(x)
              sin(x)[sin(x) - cos(x)cot(x)] = 1 - cos²(x) - cos²(x)
   sin(x)[sin(x)] - sin(x)[cos(x)cot(x)] = sin²(x) - cos²(x)
                               sin²(x) - cos²(x) = sin²(x) - cos²(x)
                                         + cos²(x)              + cos²(x)
                                             sin²(x) = sin²(x)
                                           - sin²(x)  - sin²(x)
                                                     0 = 0

3. 1 + sec²(x)sin²(x) = sec²(x)
           sec²(x)             sec²(x)
      cos²(x) + sin²(x) = 1
                    cos²(x) = 1 - sin²(x)
                  √cos²(x) = √(1 - sin²(x))
                     cos(x) = √(1 - sin²(x))
               cos⁻¹(cos(x)) = cos⁻¹(√1 - sin²(x))
                                 x = 0

4. -tan²(x) + sec²(x) = 1
               -1               -1
      tan²(x) - sec²(x) = -1
                    tan²(x) = -1 + sec²
                  √tan²(x) = √(-1 + sec²(x))
                     tan(x) = √(-1 + sec²(x))
            tan⁻¹(tan(x)) = tan⁻¹(√(-1 + sec²(x))
                             x = 0
5 0
3 years ago
How many real fifth roots does - 1,024 have?
atroni [7]
I think 1,024 has 4.
3 0
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