The height has to be 4, 5, or 6, so the width would be 15, 12, and 10 respectively.
4*15=60
5*12=60
6*10=60
These are the only whole numbers between 4 and 6, as whole numbers are non-decimal numbers greater than or equal to 0
Perpendicular lines, C is the answer.
To solve this equation, Simplify the first and then the second.
First will be solved like: -y=3x+3, y=-3x-3. The second will be simplified as: 9y=3x+2, y=1/3x+2/9. Then you divide by 3.t.
I’m not sure but I think 4 classes have between 27 and 31 students
The first $1500 is taxes at 2%, which comes out to $30.
The next $3000 is taked at 3%, which comes out to $90.
This leaves a remainder of $8000-($1500+$3000). That'd be $3500.
Williams must pay 6% of that $3500, or $210.
His total tax bill would then be $210+$90+$30, or $330.
Solution
Divide the figure into 2
Draw a horizontal line to cut the shape into 2 squares at the top
Area of the top 2 squares = 2 x 1 = 2 squared units
Area of the other part = 5 x 3 = 15 squared units
Area of the figure = 15 + 2 = 17 squared units
The answer is 17 squared units
