Answer:
- It's not possible to earn an A in the course
- I must have a 73 or MORE to earn a B in the course
Step-by-step explanation:
The average obtained at the end of the course will be:
Where x is the grade obtained in the final examination and av is the final average. To obtain an A, av has to be at least 90, av≥90, and to obtain an B, av has to be at least 80, av≥80
- Is an A in the course possible?
So, if we get 100 on the final average:
x = 100,
av = (85+78+84+100)/4 = 86,75 and 86,75∠90.
<em>Answer: No, the higher grade obtained would be 86,75.</em>
- What grade you must have in the final to earn a B in the course
To earn a B, av≥80:
<em>Answer: I must have a 73 or MORE to earn a B in the course</em>
Answer:
10
100
1000
Step-by-step explanation:
I had a quiz on that the other day got 100%
Answer:
(-6,0)
Step-by-step explanation:
the y-axis is any (x number, 0)
Answer:
Complete solution is given in the images attached below for better demonstration
Perpendicular lines refers to a pair of straight lines that intercept each other. The slopes of this lines are opposite reciprocal, meaning that it's multiplication is -1.
On this case they give you the equation of a line and a point, and is asked to find the equation of a line that is perpendicular to the given one, and that passes through this point.
-2x+3y=-6 Add 2x in both sides
3y=2x-6 Divide by 3 in both sides to isolate y
y=2/3x-6/3
The slope of the given line is 2/3, which means that the slope of a line perpendicular to this one, needs to be -3/2. Now you need to find the value of b or the y-intercept by substituting the given point into the formula y=mx+b, where letter m represents the slope.
y=mx+b Substitute the given point and the previous slope found
-2=(-3/2)(6)+b Combine like terms
-2=-9+b Add 9 in both sides to isolate b
7=b
The equation that represents the line perpendicular to -2x+3y=-6 and that passes through the point (6,-2), is y=-3/2x+7.
