Answer:
the question is incomplete, so I looked for a similar one:
<em>After the release of radioactive material into the atmosphere from a nuclear power plant, the hay was contaminated by iodine 131 ( half-life, 8 days). If it is all right to feed the hay to cows when 10% of the iodine 131 remains, how long did the farmers need to wait to use this hay? </em>
iodine's half life (we are given x, we need to find b):
0.5A₀ = A₀eᵇˣ
x = 8 days
we eliminate A₀ from both sides
0.5 = eᵇ⁸
ln 0.5 = ln eᵇ⁸
-0.69315 = b8
b = -0.69315 / 8 = -0.08664
since the farmers need to wait until only 10% of the iodine remains (we already calculated b, now we need to find x):
0.1A₀ = A₀eᵇˣ
0.1 = eᵇˣ
ln 0.1 = bx
where b = -0.08664
x = ln 0.1 / -0.08664 = -2.302585 / -0.08664 = 26.58 days
<span>$152.51
y o u r a n s w e r i s a b o v e
</span>
Answer:
The equation of the straight line is 4x +y = 1
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given points are (-1,5) and ( 2,-7)
Slope of the line
slope of the line m = -4
<u><em>Step(ii):-</em></u>
The equation of the straight line passing through the point (-1,5) and having slope 'm' = -4
y - 5 = -4 ( x-(-1))
y -5 = -4 x -4
4 x + y -5 +4=0
4x +y -1 =0
<u><em>Final answer:-</em></u>
The equation of the straight line is 4x +y = 1
<u><em> </em></u>
<h3>I'll teach you how to factor 6x^2y − 3xy − 24xy^2 + 12y^2</h3>
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6x^2y − 3xy − 24xy^2 + 12y^2
Apply exponent rule:
6x^2y-3xy-24xyy+12yy
Rewrite 12 as 4*3
Rewrite -24 as 8*3
Rewrite 6 as 2*3
2*3x^2y-3xy+8*3xyy+4*3yy
Factor out common term 3y:
3y(2x^2-x-8xy+4y)
Factor 2x^2-x-8xy+4y:
3y(2x-1)(x-4y)
Your Answer Is 3y(2x-1)(x-4y)
plz mark me as brainliest if this helped :)
Answer:
g(x) = -|x| + 1
Step-by-step explanation:
Let g(x) be the transformation function
-|x| reflects f(x) across the x-axis. Add 1 to move the result up one unit
So, g(x) = -|x| + 1
