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Nady [450]
3 years ago
10

Bennett has 107 photographs to place in the school yearbook. He will put the same number of photos on each of the 13 pages. if h

e can put 4 pictures in a row, how many photographs will not be placed in the yearbook? Explain.
Mathematics
2 answers:
HACTEHA [7]3 years ago
7 0

Answer:

3

Step-by-step explanation: if he has 2 rows of four on each page and 13 pages 8 * 13 is 104 and 107 -  104 is 3

labwork [276]3 years ago
7 0

Answer: im pretty sure is 3

Step-by-step explanation: but sorry i dont know how to explain it

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The volume of a cube is 1.8 m3. Find the length of its edge to the nearest tenth of a
Firdavs [7]

The length of an edge is the cubic root of the volume.

Cubic root 1.8 = 1.2 meters

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2 years ago
What is two over eight minus 1 over 2
avanturin [10]

The answer is -1/4 I’m in 11th grade trust me

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Is it possiible to develop a place without a prior plan​?give four points
Volgvan
Uhmmmm is there a picture of the problem i’m confused
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If g(x) = 3(x + 10), what is the value of the<br> function when x = -8?<br> O<br> -8<br> -2<br> 24
Gala2k [10]

Answer:

6 which is none of your answers.

Are you sure your function is right?

Is value to plug in x=-8?

Step-by-step explanation:

To find the value of the function at x=-8, you replace x with -8 in the function.

g(x)=3(x+10)

g(-8)=3(-8+10)

g(-8)=3(2)

g(-8)=6

7 0
3 years ago
Read 2 more answers
In order to ensure efficient usage of a server, it is necessary to estimate the mean number
juin [17]

Answer:

a. [36.19;39.21]

b. Reject the null hypothesis. The population mean of users that are connected at the same time is greater than 35.

Step-by-step explanation:

Hello!

Your study variable is,

X: "number of users of one server at a time"

The objective is to estimate the mean, for this, a sample of n=100 times was taken and the standard deviation S= 9.2 and the sample mean is X[bar]= 37.7 were calculated.

You need to study the population mean, for this you need your variable to have at least normal distribution. Since you don't have information about its distribution, but the sample is big enough (n≥30) you can apply the Central Limit Theorem and approximate the distribution of the sample mean X[bar] to normal:

X[bar]≈N(μ;σ²/n)

a. With this approximation, you can construct the 90% Confidence Interval using the approximate Z

[X[bar] ± Z_{1-\alpha /2} * S/√n]

Z_{1-\alpha /2} = Z_{0.95} = 1.64

[37.7± 1.64* 9.2/√100]

[36.19;39.21]

b. You need to test if the population mean is greater than 35 with a level of significance of 1%.

The hypothesis is:

H₀: μ ≤ 35

H₁: μ > 35

α: 0.01

This is a one-tailed test so you have only one critical level (right tail):

Z_{1\alpha } = Z_{0.99} = 2.33

This means that if the value of the calculated statistic is equal or greater than 2.33 you will reject the null Hypothesis.

If the value is less than 2.33 you will support the null hypothesis.

The statistic is:

Z=<u> X[bar] - μ </u>= <u> 37.7 - 35 </u> = 2.93

       S/√n           9.2/10

The value 2.93 > 2.33, so you reject the null hypothesis. This means that the population mean of users that are connected at the same time is greater than 35.

<u><em>Note: </em></u><em>To make the decision using the interval calculated on a), the hypothesis should have been two-tailed and the confidence and significance levels complementary.</em>

I hope it helps!

7 0
3 years ago
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