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Nady [450]
3 years ago
10

Bennett has 107 photographs to place in the school yearbook. He will put the same number of photos on each of the 13 pages. if h

e can put 4 pictures in a row, how many photographs will not be placed in the yearbook? Explain.
Mathematics
2 answers:
HACTEHA [7]3 years ago
7 0

Answer:

3

Step-by-step explanation: if he has 2 rows of four on each page and 13 pages 8 * 13 is 104 and 107 -  104 is 3

labwork [276]3 years ago
7 0

Answer: im pretty sure is 3

Step-by-step explanation: but sorry i dont know how to explain it

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Light, Volume

Step-by-step explanation:

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Count with me :) deqeweDr3<br><br> 1
Eduardwww [97]

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no

Step-by-step explanation:

because i siad so

4 0
2 years ago
Two friends, Sasha and Maria, are growing out their hair. They plan to cut it off at a certain
34kurt

Answer:

13 months, 49 cms

Explanation:

For Sasha, multiply 3 and 13 together for the growth per month. You should get 39, then add the 10 cm Sasha already has. The sum is 49.

For Maria, multiply 13 and 1 for the growth per month. You should get 13, then add the 36 Maria already has. The sum is also 49.

Hope this helps!

8 0
3 years ago
The endpoints of PQ are (4,1) and Q(4,8)
tatuchka [14]

Answer:

Search this up on google to find out what the answer is because no one is going to know how to do it.


5 0
3 years ago
Adam must fly home to city A from a business meeting in city B. One flight option flies directly to city A from​ B, a distance o
g100num [7]

Answer:

The value  is  k =109.6 \ miles

Step-by-step explanation:

The diagram illustrating the question is shown on the first uploaded image

From the question we are told that

   The distance from city A to B is   AB =  467.3 miles

   The bearing from B to  C is  \theta_{BC} =  N 28.7E

   The bearing from B to  A is  \theta_{BA} =  N 60.7E

   The  bearing from A to  B is   \theta_{AB} =  S60.7W

    The  bearing from A to  C is   \theta_{AC} =  S79.1W

Generally from the diagram

     \theta_A  =  180 - 60.7 -79.1

=>  \theta_A  =  40.2 ^o

Also

     \theta_B  =  32^o

and  

      \theta_C  =  180 - (\theta_A  +\theta_B )

=>   \theta_C  =  180 - (40.2  + 32 )

=>   \theta_C  =  107.8 ^o

Generally according to Sine Rule

     \frac{BC}{sin (\theta_A)}  = \frac{CA}{sin (\theta_B)} =\frac{AB}{sin (\theta_C)}

=>   \frac{BC}{sin (40.2)}  = \frac{CA}{sin (32)} =\frac{467.3 }{sin (107.8)}    

So

     \frac{BC}{sin (40.2)}  = \frac{467.3 }{sin (107.8)}

=>  BC = 316.8 \ miles

Also  

    \frac{CA}{sin (32)} =  \frac{467.3 }{sin (107.8)}

    CA = 260 .1 \ miles

Generally the additional flyer miles that Adam will receive if he takes the connecting flight rather than the direct​ flight is mathematically represented as

      k = [CA +BC]  - AB

=>     k = [260 .1 +316.8]- 467.3

=>  k =109.6 \ miles

4 0
3 years ago
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