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Elanso [62]
3 years ago
13

A box is to be constructed with a rectangular base and a height of h cm. the length, l, of the box is 10 cm, and the width, w, i

s twice the height. which quadratic equation best models the volume of the box?
Mathematics
1 answer:
vivado [14]3 years ago
5 0
There are several information's already given in the question. based on those information's, the answer can be easily determined.
Height of the box = h cm
Length of the box = 10 cm
Width of the box = 2h
Then
Volume of the box = Length * height * width
                              = 10 * h * 2h cubic cm
                              = 20h^2 cm^3
I hope that the above procedure is clear enough for you to understand and it has actually come to your desired help.
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Ya'll gone (pt) make me loose my (pt) cool, up in here, (pt) up in here! (pt)

Ya'll gone make (pt) me bust a (pft) sweat, up in here, (pt) up in here! (pt)

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Why should I battle a krusty old man

When you can't even defeat a little weak Peter Pan

Ya (B) lucky this is (pt) only a beatbox (pt) battle

Cause in a real battle (pt) I make ya feel rattled

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(B) Ya'll gone (pt) make me-sla-Bea-pt-ha-sss-ssslipita-pa-a-pt-A-prdrdrdr-prdrdrdr (pt) ha-tugh-ha

(B) Ya'll gone (pt) make (B) me-tugh-ha-Bea-pt-ha-sss-ssslipita-pa-a-pt-ki-prrsk-kt-Bea-pt-ka-tugh

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Bm-Tha-A-Tha-Ay-Bm-Bm

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Bm-Tha-Ay-Bm-Nos-Bm-the-A-pt-Bm

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Step-by-step explanation:

4 0
3 years ago
Please help ASAP
REY [17]
<h3><u>Answer :</u><u>-</u><u> </u></h3>

<u>\frac{1}{2}</u>

<h3><u>Question :- </u></h3>

find \:  \frac{ - 4}{5}  \times  \frac{3}{7}  \times  \frac{15}{16} \times ( \frac{ - 14}{9} )

<h2><u>Solution :- </u></h2>

<h3><u>First </u><u>way:</u></h3>

<h3>• we have ; </h3>

\frac{ - 4}{5}  \times  \frac{3}{7}  \times  \frac{15}{16}  \times ( \frac{ - 14}{9} )

<h3>So then , </h3>

=  >  \: ( -  \frac {4 \times 3}{5 \times 7} ) \times ( \frac{15 \times ( - 14)}{16 \times 9}

=  >  \:  \frac{ - 12}{35}   \times ( \frac{ - 35}{24} ) =  \frac{ - 12 \times ( - 35)}{35 \times 24}  =  \frac{1}{2}

<h3><u>Second way : </u></h3>

\frac{ - 4}{5}  \times  \frac{3}{7}  \times  \frac{15}{16}  \times  (\frac{ - 14}{9} )

=  >  \: ( \frac{ - 4}{5}  \times  \frac{15}{16} ) \times  \binom{3}{7}  \times ( \frac{ - 14}{9} )

[ ↑ Using commutativity and Associativity ] ...

\frac{ - 3}{4}  \times ( \frac{ - 2}{3} ) =  \frac{1}{2}

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