Use the linear slope formula to solve for m:
m=(y2-y1)/(x2-x1)
using the points (-1,1) and (1,5) you can find the slope for the first interval:
m=(5-1)/(1-(-1))
m=4/2
m=2
you can double check by using the same formula on the second interval, which is (1,5) to (3,9).
m=(9-5)/(3-1)
m=4/2
m=2
therefore, the rate of change is 2.
Answer:
3
Step-by-step explanation:
The principal, real, root of:
=1.73205081
All roots:
1.73205081
−1.73205081
3 is not a perfect square
Answer:
Learning to subtract rational numbers by adding the additive inverse can be explained to your child as being the same as finding the opposite. This can even be described to your child as being a similar concept to one that they have worked with in the past where subtraction is the opposite of addition.
Additive inverse can be defined as adding a number with the opposite or the negative of that number to equal zero. The additive inverse of 1 is (-1), the additive inverse of 2 is (-2) and so on.
Example: 5 + (-5) = 0
In this example, (-5) is the additive inverse.
You can then take additive inverse one step when finding the additive inverse when subtracting rational numbers.
Example: 7 - 4 = 7 + (-4)
3 = 3
When finding the inverse, it is important to keep in mind that what you do to one side, you must do the opposite to another. In the example above, because you subtracted a positive four on one side, you are going to add a negative four to the other. This will make the equation equal on both sides.
Step-by-step explanation:
Answer:
the triangle flipped over the y axis
We know that for every 5 red bricks there were 2 gray bricks.
The total amount of red bricks and grey bricks in this sample is 7.
5 red bricks + 2 grey bricks = 7 bricks
Now, we divide 175 "total number of bricks used" by 7 "5 red bricks + 2 grey bricks = 7 bricks" and we will get a quotient of 25.
Now we know that 25 bricks is
of the wall. The gray bricks are
so we can multiply 25 by 2 and we will get a product of 50. If 1/7 = 25 grey bricks so 2/7 would be the grey bricks.
175 - 50 = number of red bricks.
Therefore, there were 125 red bricks.