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sattari [20]
3 years ago
6

SOMEONE PLEASE HELP ASAP

Mathematics
2 answers:
Over [174]3 years ago
6 0

Answer:

x=<em>1</em><em>3</em><em> </em><em>and</em><em> </em><em>y</em><em> </em><em>=</em><em>1</em><em>3</em><em>√</em><em>3</em>

Step-by-step explanation:

in right angled triangle

relation between

hypotenuse and perpendicular is given by sin angle

sin 60=p/h

sin60=y/26

y=sin60×26=13√3

by Pythagoras law

h²=p²+b²

26²=(13√3)²+x²

x²=26²-507=169

x=√169=13

Nezavi [6.7K]3 years ago
4 0

Answer:

What were is it

Step-by-step explanation:

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Answer:

Option D)Neither solution is extraneous.

Step-by-step explanation:

we have

\sqrt{11-2x}=\sqrt{x^{2}+4x+4}

we know that

two possible solutions are x=-7 and x=1

<u><em>Verify each solution</em></u>

Substitute each value of x in the expression above and interpret the results

1) For x=-7

\sqrt{11-2(-7)}=\sqrt{-7^{2}+4(-7)+4}

\sqrt{25}=\sqrt{25}

5=5 ----> is true

therefore

x=-7 is not a an extraneous solution

2) For x=1

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therefore

x=1 is not a an extraneous solution

therefore

Neither solution is extraneous

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<h3>What is the area of the rectangle?</h3>

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The area of a rectangle can be calculated using the following formula:

Rectangle area = length x width

We have:

A rectangular building for a gym is three times as long as it is wide. Just inside the walls of the building, there is a 6ft rectangular track along the walls of the gym and has an area of 7000ft²

Let x be the width of the rectangle.

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