Ask question

Ask question

All categories

3 years ago

5

Markuo had 20 minutes to do a three-problem quiz. He spent 10 1 4 minutes on question A and 6 4 5 minutes on question B. How muc

h time did he have left for question C?

1 answer:

love history [14]3 years ago

3 0

It’s question b bro it’s so easy it’s 6-3

You might be interested in

What is the length of the hypotenuse of the triangle?

masha68 [24]

10 star-root 2 end units

8 0

2 years ago

Read 2 more answers

What is the domain of the function f(x)=45/(x-23)?

galben [10]

Domain is the set of numbers you can use
usually, domain=all real numbers except those that divide by zero

so find those exceptions
find what numbers make deonenator equal to 0 and exclude them
x-23 is denom
x-23=0
x=23

doman is all real numbers except 23

5 0

4 years ago

Read 2 more answers

A rectangular prism. The rectangular base has a length of 5 centimeters and width of 4 centimeters. What are the dimensions of t

AVprozaik [17]

Answer:

dimension is 5cm * 4 cm

Step-by-step explanation:

As the plane is parallel to the base, the ratio between plane's length and width is equal to the ratio of that of the base. -> similar shape.

Moreover, it also divided the rectangular prism into 2 smaller rectangular prism. hence the plane is identical to the base. Hence, same dimension.

see photo

3 0

3 years ago

describe the graph of y=x^2 in words so that someone in a different room could understand exactly what it looks like explain wha

vladimir2022 [97]

Answer:

* y = x² is a quadratic function represented graphically by parabola opened upward with minimum vertex (0 , 0) and y-intercept = 0

* The graph will move vertically up 5 units and its vertex will be

(0 , 5)

Step-by-step explanation:

∵ y = ax² + bx + c is a quadratic function

Represented graphically by parabola, its vertex is (-b/2a , f(-b/2a))

∵ The value of a > 0 then the parabola open upward

∴ Its vertex is minimum

∵ The value of a < 0 then the parabola oped downward

∴ Its vertex is maximum

∵ The coefficient of x² = 1

∴ The parabola open upward

∵ The coefficient of x = 0

∴ Its vertex is (0 , 0) ⇒ x = 0/2(1) = 0 , f(0) = (0)² = 0

∴ The y-intercept = 0

∴ The parabola is oped upward , has minimum vertex (0 , 0)

and passing through the origin

∵ 5 is added to y = x² , that means we add 5 to f(x) ⇒ f(x) + 5

∴ y = x² + 5 ⇒ that means the graph move vertically up 5 units

∴ Its vertex will be (0 , 5)

5 0

3 years ago

Solve using substitution or elimination.<br><br> y = x + 1<br> 2x - 5y = 4

andrew-mc [135]

Substitute y = x + 1 into 2x - 5y = 4

-3x - 5 = 4

Solve for x in -3x - 5 = 4

x = -3

Substitute x = -3 into y = x + 1

y = -2

Therefore,

<u>x = -3</u>

<u>y = -2</u>

5 0

3 years ago