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3 years ago

Solve for x, where x>0 and 5x^2+9x-18=0. Express your answer as a simplified common fraction.

Mathematics

1 answer:

yanalaym [24]3 years ago

8 0

x is gonna be 3 but I need to be over 20 characters

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Shawn graphed the points listed below.

Semenov [28]

Answer: A. (4, 4) and (4, 5)

Step-by-step explanation:

The same x value maps onto more than one y value.

6 0

2 years ago

a) Read section 1.5 in the Yakir textbook. If you were a teacher and had 30 students in your class and wanted to know the class

OlgaM077 [116]

Answer:

Parameter

Step-by-step explanation:

Required

Parameter of Statistic

From the question, we understand that the teacher is to calculate the class average.

To calculate the class average, the teacher will use the mean function/formula, which is calculated as:

$Mean = \frac{\sum x}{n}$

Generally, mean is an example of a parameter.

<em>So, we can conclude that the teacher will use parameer</em>

7 0

3 years ago

+ 2h + 5 when g = 3 and h = 6.

Rudik [331]

Is this the whole problem because I don’t see a “g”
Anywhere I’m the problem

5 0

3 years ago

Please please help me out with this problem

Hatshy [7]

Answer:

y = 3x - 4

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, - 4) and (x₂, y₂ ) = (2, 2) ← 2 points on the line

m = $\frac{2+4}{2-0}$ = $\frac{6}{2}$ = 3

Note the line crosses the y- axis at (0, - 4) ⇒ c = - 4

y = 3x - 4 ← equation of line

6 0

3 years ago

Consider the equation x2+4x+9=0 in standard form. Which equation shows the coefficients a, b, and c correctly substituted into t

Afina-wow [57]

Answer:

Step-by-step explanation:

The general form of a quadratic equation is ax²+bx+c = 0

Given the quadratic equation x²+4x+9=0 in its standard form, on comparing with the general equation we can get the value of the constant a, b and c as shown;

ax² = x²

a = 1

bx = 4x

b = 4

c = 9

The quadratic formula is given as x = -b±√(b²-4ac)/2a

Substituting the constant;

x = -4±√(4²-4(1)(9))/2(1)

x = -4 ±√(16-36)/2

x = -4±√-20/2

x = -4±(√-1*√20)/2

Note that √-1 = i

x = -4±(i√4*5)/2

x = (-4±i2√5)/2

x = -4/2±i2√5/2

x = -2±i√5

The solution to the quadratic equation are -2+i√5 and -2i-√5

5 0

4 years ago