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AfilCa [17]
3 years ago
12

The final exam of a particular class makes up 40% of the final grade, and Moe is failing the class with an average (arithmetic m

ean) of 45% just before taking the final exam. What grade does Moe need on his final exam in order to receive the passing grade average of 60% for the class?
Mathematics
1 answer:
amm18123 years ago
6 0

Answer:

%82.5

Step-by-step explanation:

  1. The final exam of a particular class makes up 40% of the final grade
  2. Moe is failing the class with an average (arithmetic mean) of 45% just before taking the final exam.

From point 1 we know that Moe´s grade just before taking the final exam represents 60% of the final grade. Then, using the information in the point 2 we can compute Moe´s final grade as follows:

FG=0.40*FE+0.60*0.45,

where FG is Moe´s Final Grade and FE is Moe´s final exam grade. Then,

\frac{ FG-0.60*0.45}{0.40}=FE.

So, in order to receive the passing grade average of 60% for the class Moe needs to obtain in his exam:

FE=\frac{ 0.60-0.60*0.45}{0.40}=0.825

That is, he need al least %82.5 to obtain a passing grade.

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Answer:

f(x)=8x^2+73x-70

Step-by-step explanation:

We are given

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now, we are given that

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3 years ago
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Answer:

60ft

Step-by-step explanation:

Let's x, y be the width and length of the surrounding rectangle. Since the area is 450 sq feet, this means xy = 450 or y = 450/x

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f(x,y) = 2x + y

This is something we need to minimize. We can start by substituting y = 450/x

f(x) = 2x + 450/x

Let's take the first derivative of this function and set it to 0

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Answer:

The value of x would be 16.

Step-by-step explanation:

In a data,

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