Is it me or are these questions not recently?
1 answer:
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Answer:
ΔRMS ≅ ΔRQS by AAS
Step-by-step explanation:
See the diagram attached.
Given that ∠ RMS = ∠ RQS and N is any point on RS and ∠ MRS = ∠ SRQ.
Therefore, between Δ RMS and Δ RQS, we have
(i) ∠ RMS = ∠ RQS {Given}
(ii) ∠ MRS = ∠ SRQ {Also given} and
(iii) RS is the common side.
So, by angle-angle-side i.e. AAS criteria we can write ΔRMS ≅ ΔRQS. (Answer)
Answer:
view the picture
Step-by-step explanation:
It is self explanatory
Answer:
The answer is
<h2>Step-by-step explanation:
Equation of a line is y = mx + c
where
m is the slope
c is the y intercept
To find the equation of the parallel line we must first find the slope of the original line
From the question the original line is
y=1/4x+5
Comparing with the general equation above
Slope = 1/4
Since the lines are parallel their slope are also the same
Slope of parallel line = 1/4
So the equation of the line using point
(2,-9) and slope 1/4 is
<h3>We have the final answer as
<h3>Hope this helps you