Answer:
![Q_1 = 24](https://tex.z-dn.net/?f=%20Q_1%20%3D%2024)
![Q_3 = 29](https://tex.z-dn.net/?f=Q_3%20%3D%2029)
![IQR= Q_3 -Q_1 = 29-24 =5](https://tex.z-dn.net/?f=%20IQR%3D%20Q_3%20-Q_1%20%3D%2029-24%20%3D5)
Step-by-step explanation:
For this case we have the following dataset:
25,21,26,24,29,33,29,25,19,24
The first step is order the data on increasing order and we got:
19, 21, 24, 24, 25, 25, 26, 29, 29 , 33
For this case we have n=10 an even number of data values.
We can find the median on this case is the average between the 5 and 6 position from the data ordered:
![Median = \frac{25+25}{2}=25](https://tex.z-dn.net/?f=%20Median%20%3D%20%5Cfrac%7B25%2B25%7D%7B2%7D%3D25)
In order to find the first quartile we know that the lower half of the data is: {19, 21, 24, 24, 25}, and if we find the middle point for this interval we got 24 so this value would be the first quartile ![Q_1 = 24](https://tex.z-dn.net/?f=%20Q_1%20%3D%2024)
For the upper half of the data we have {25,26,29,29,33} and the middle value for this case is 29 and that represent the third quartile ![Q_3 = 29](https://tex.z-dn.net/?f=Q_3%20%3D%2029)
And finally since we have the quartiles we can find the interquartile rang with the following formula:
![IQR= Q_3 -Q_1 = 29-24 =5](https://tex.z-dn.net/?f=%20IQR%3D%20Q_3%20-Q_1%20%3D%2029-24%20%3D5)